$\frac{a^{m}}{a^{n}}=a^{m-n}\\\\a^{-m}=\frac{1}{a^{m}}\\\\\\\frac{x^{2}y^{-3}}{x^{5}y^{2}}=x^{(2-5)}*y^{(-3-2)}\\\\ = x^{-3}*y^{-5}\\\\=\frac{1}{x^{3}y^{5}}$

7 0

3 years ago

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Alex rolls a 6-sided dice ten times.

Angelina_Jolie [31]

Answer:

Hello Love! The median is simply just the number in the middle so sense we have 2 numbers in the middle our median will be 3 and 6

The mean is when you add up the numebers then divide by how many numbers there are so...

3 + 2 + 4 + 6 + 3 + 6 + 1 + 2 + 5 + 4 = 36 so 36 divided by 10 is 3.6

The range is simply just the biggest number in the sequence subtracted by the smallest number so... 6 - 1 = 5 so 5 would be our range!

Hope this helps you.

3 0

3 years ago