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NeTakaya
2 years ago
12

State the major different between fours types of computers

Computers and Technology
1 answer:
Igoryamba2 years ago
8 0

Answer:

1. Supercomputers

Supercomputers are very expensive and very fast. They are the most powerful computers we have in the world.

Supercomputers are optimized to execute only a small number of programs. This makes it possible for them to execute these few programs at a very high speed. Due to their inhibiting cost, they are used in high-end places like in scientific research centers. The supercomputer consists of thousands of processors, allowing it to clock in at very high speeds measured by petaflops.

These computer types are also very large in size due to the numerous parts and components involved in their design.

A good example of a supercomputer is Tianhe-2, which is located in the National Supercomputer Center in Guangzhou, China. It features 3.12 million cores, allowing it to run at speeds of 33.86 petaflops.

2. Mainframe Computers

These are large and expensive computers that are capable of supporting thousands of users simultaneously. They are mostly used by governments and large organizations for bulk data processing, critical applications, and transaction processing. They are ranked below supercomputers.

3. Minicomputers

Minicomputers are mid-sized computers. In terms of size and power, they are ranked below mainframes. A minicomputer is a multiprocessing system capable of supporting from 4 to about 200 users simultaneously.

The use of the term minicomputer has diminished since the introduction of microprocessors. These machines are now more commonly called midrange computers.

4. Microcomputers

A microcomputer, also known as a personal computer, is designed to be used by one user at a time. The term microcomputer relates to the microprocessor that is used for the purpose of processing data and instruction codes. These are the most common computer types since they are not very expensive

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"Write a program that calculates the balance of a savings account at the end of a period of time. It should ask the user for the
Akimi4 [234]

Answer:

#include <iostream>

#include <fstream>

using namespace std;

int main() {

// Definitions

       double annualInterest;          // The annual interest rate

       double balance;                 // The account balance

       int months;                     // Total number of months

       double totalDeposit  = 0.0;     // Total deposited value

       double totalWithdraw = 0.0;     // Total withdrawn value

       double earnedInterest= 0.0;     // The earned amount

       double deposited;               // Monthly deposited value

       double withdrawn;               // Monthly withdrawn value

// Get the initial required data.

       

       cout<<"Please enter the annual interest rate,\n";

       cout<<"   Interest rate: ";

       cin >>annualInterest;

       cout<<"--------------------------------------------\n";

       cout<<"Please enter the starting balance,\n";

       do{

           cout<<"[the number could not be negative]\n";

           cout<<"Starting Balance: ";

           cin >>balance;

       }while(balance<0);

       cout<<"--------------------------------------------\n";

       cout<<"Please enter the number of months,\n";

       do{

           cout<<"[the number could not be less than 0]\n";

           cout<<"Number of months: ";

           cin >>months;

       }while(months<0);

// Iterated Loop to get all the months data.

       for(int month=1; month <= months; month++){

// Get the deposited value during that month.

           cout<<"Enter the deposited value during month "

               <<month<<",\n";

           do{

               cout<<"[the value could not be less than 0]\n";

               cout<<" Deposited value: ";

               cin >>deposited;

           }while(deposited<0);

           

           totalDeposit += deposited;

           balance += deposited;

// Get the withdrawn value during that month.

           cout<<"Enter the withdrawn value during month "

               <<month<<",\n";

           do{

               cout<<"[the value could not be less than 0]\n";

               cout<<" Withdrawn value: ";

               cin >>withdrawn;

           }while(withdrawn<0);

           

           totalWithdraw += withdrawn;

           balance -= withdrawn;

// Negative balance close the program.

           if(balance < 0){

               cout<<"Sorry, the account has been closed due to\n";

               cout<<"the negative balance.\n";

                 break;

// Calculate value due to the interest rate.

           }

      else {

               earnedInterest += (annualInterest/12) * balance;

               //        monthly interest rate

               balance += (annualInterest/12) * balance;

           }

       }

  // Display the statistics,

      ofstream file;

      file.open ("Report written to Report.txt");

      file << "Report written to Report.txt\n";

       file.close();

       cout<<"The ending balance: "<<balance<<std::endl;

       cout<<"   Total deposited: "<< totalDeposit<<std::endl;

       cout<<" Total withdrawals: "<< totalWithdraw<<std::endl;

       cout<<"   Earned interest: "<< earnedInterest<<std::endl;

       cout<<"============================================\n";

 return 0;

   }

   

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3 years ago
The return value is a one-dimensional array that contains two elements. These two elements indicate the rows and column indices
erma4kov [3.2K]

Answer:

In Java:

import java.util.Scanner;  

import java.util.Arrays;  

public class Main  {  

public static void main(String args[])  {  

Scanner input = new Scanner(System.in);

int row, col;  

System.out.print("Rows: ");    row = input.nextInt();

System.out.print("Cols: ");     col = input.nextInt();  

int[][] Array2D = new int[row][col];

System.out.print("Enter array elements: ");

for(int i =0;i<row;i++){    

    for(int j =0;j<col;j++){

        Array2D[i][j] = input.nextInt();  

    }     }

 

int[] maxarray = findmax(Array2D,row,col);

System.out.println("Row: "+(maxarray[0]+1));

System.out.println("Column: "+(maxarray[1]+1));

}  

public static int[] findmax(int[][] Array2D,int row, int col)   {  

int max = Array2D[0][0];

int []maxitem = new int [2];

for(int i =0;i<row;i++){

    for(int j =0;j<col;j++){

        if(Array2D[i][j] > max){  

            maxitem[0] = i;

            maxitem[1] = j; } }    }

 

return maxitem;  

}  

}

Explanation:

The next two lines import the scanner and array libraries

<em>import java.util.Scanner;   </em>

<em>import java.util.Arrays;   </em>

The class of the program

<em>public class Main  {  </em>

The main method begins here

<em>public static void main(String args[])  {  </em>

The scanner function is called in the program

<em>Scanner input = new Scanner(System.in);</em>

This declares the array row and column

int row, col;

This next instructions prompt the user for rows and get the row input  

System.out.print("Rows: ");    row = input.nextInt();

This next instructions prompt the user for columns and get the column input  

System.out.print("Cols: ");     col = input.nextInt();  

This declares the 2D array

int[][] Array2D = new int[row][col];

This prompts the user for array elements

System.out.print("Enter array elements: ");

The following iteration populates the 2D array

<em> for(int i =0;i<row;i++){    </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         Array2D[i][j] = input.nextInt();   </em>

<em>     }     } </em>

This calls the findmax function. The returned array of the function is saved in maxarray  

int[] maxarray = findmax(Array2D,row,col);

This prints the row position

System.out.println("Row: "+(maxarray[0]+1));

This prints the column position

System.out.println("Column: "+(maxarray[1]+1));

The main method ends here

}  

The findmax function begins here

public static int[] findmax(int[][] Array2D,int row, int col)   {  

This initializes the maximum to the first element of the array

int max = Array2D[0][0];

This declares maxitem. The array gets the position of the maximum element

int []maxitem = new int [2];

The following iteration gets the position of the maximum element

<em>for(int i =0;i<row;i++){ </em>

<em>     for(int j =0;j<col;j++){ </em>

<em>         if(Array2D[i][j] > max){  </em>

<em>             maxitem[0] = i; </em><em>-- The row position is saved in index 0</em><em> </em>

<em>             maxitem[1] = j;  </em><em>-- The column position is saved in index 1</em><em>} }    } </em>

This returns the 1 d array

return maxitem;  

}  

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Answer:

Answer is A: place absorbent chemical packets in the camera cover

Explanation:

Keith is required to carry adequate gear while going for a shoot. And in this case, he should carry anything that will protect his camera from the ocean and rainwater. By anything, I mean anything that Keith will use to stay dry. Using an air conditioner would be the worst idea. An air conditioner might blow the air towards your camera. Placing the camera in its case will ensure that it is dry and Keith will keep on shooting. Placing absorbent chemical packets in the camera cover will ensure that any water droplets that might fall on the cover of the camera will be absorbed. The point here is to keep dry.

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