I have no idea what the answer is

Although xenon and neon are noble gases and therefore do not typically form bonds, weak attractive forces do exist between atoms

mariarad [96]

The statement that best explains why xenon has a higher boiling point than neon is that xenon has more electrons than neon.

<h3>What are intermolecular forces?</h3>

The term intermolecular forces are the force that hold matter together in a particular state such as solid liquid or gas. The more the electrons present, the greater the polarizability and the greater dispersion forces at work.

Thus, the statement that best explains why xenon has a higher boiling point than neon is that xenon has more electrons than neon.

Learn more about intermolecular forces:brainly.com/question/9007693

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5 0

1 year ago

Which of the following would release the most heat upon cooling from 75*C to 50*C?

Tresset [83]

The answer should be 10g.

4 0

3 years ago

Read 2 more answers

Porquê que o potássio é mais reativo que o cálcio? urgente!

saul85 [17]

Answer: O potássio possui apenas um elétron de valência. ... Considerando que o cálcio possui dois elétrons de valência, requer mais energia para a remoção de um elétron de valência. Devido a esse potássio, é mais reativo que o cálcio.

Explanation:

4 0

2 years ago

I NEED HELP PLEASE!!!! CHEMISTRY QUESTION: If 38 g of Li3P and 15 grams of Al2O3 are reacted, what total mass of products will r

maksim [4K]

Answer:

21.5 g.

Explanation:

Hello!

In this case, since the reaction between the given compounds is:

$2Li_3P+Al_2O_3\rightarrow 3Li_2O+2AlP$

We can see that according to the law of conservation of mass, which states that matter is neither created nor destroyed during a chemical reaction, the total mass of products equals the total mass of reactants based on the stoichiometric proportions; in such a way, we first need to compute the reacted moles of Li3P as shown below:

$n_{Li_3P}^{reacted}=38gLi_3P*\frac{1molLi_3P}{51.8gLi_3P}=0.73molLi_3P$

Now, the moles of Li3P consumed by 15 g of Al2O3:

$n_{Li_3P}^{consumed \ by \ Al_2O_3}=15gAl_2O_3*\frac{1molAl_2O_3}{101.96gAl_2O_3} *\frac{2molLi_3P}{1molAl_2O_3} =0.29molLi_3P$

Thus, we infer that just 0.29 moles of 0.73 react to form products; which means that the mass of formed products is:

$m_{Li_2O}=0.29molLi_3P*\frac{3molLi_2O}{2molLi_3P} *\frac{29.88gLi_2O}{1molLi_2O} =13gLi_2O\\\\m_{AlP}=0.29molLi_3P*\frac{2molAlP}{2molLi_3P} *\frac{57.95gAlP}{1molAlP} =8.5gAlP$

Therefore, the total mass of products is:

$m_{products}=13g+8.5g\\\\m_{products}=21.5g$

Which is not the same to the reactants (53 g) because there is an excess of Li₃P.

Best Regards!

7 0

2 years ago

How many kilograms of solvent (water) must 0.71 moles of KI be dissolved in to produce a 1.93 m solution?

GalinKa [24]

Answer: kg= 0.37

Explanation:

Use the molality formula.

M= m/kg

6 0

3 years ago