Type the appositive phrase in this sentence. "cookies with chocolate chunks," the winning recipe, received $100.

1 answer:

5 0

Answer is: the winning recipe.
An appositive is a noun or noun phrase that renames another noun right beside it. The appositive can be a short or long combination of words.
Another example: Problem number 19, the final question, was difficult - the final question is the appositive phrase in this sentence.

You might be interested in

Beginning with commercial grade hydrochloric acid, 1.00 • 10^2 mL of a 12.4 M HCl is added to water to bring the total volume if

MatroZZZ [7]

Concentration=mass/volume.

This should help.

3 0

3 years ago

Chloroform, CHCl3, reacts with chlorine, Cl2, to form carbon tetrachloride, CCl4, and hydrogen chloride, HCl. In an experiment 2

erastovalidia [21]

Answer:

Chloroform= limiting reactant

0.209mol of CCl4 is formed

And 32.186g of CCl4 is formed

Explanation:

The equation of reaction

CHCl3 + Cl2= CCl4 + HCl

From the equation 1 mol of

CHCl3 reacts with 1mol Cl2 to yield 1mol of CCl4

From the question

25g of CHCl3 really with Cl2

Molar mass of CHCl3= 119.5

Molar mass of Cl2 = 71

Hence moles of CHCl3= 25/119.5 = 0.209mol

Moles of Cl2 = 25/71 = 0.352mol

Hence CHCl3 is the limiting reactant

Since 1 mole of CHCl3 gave 1mol of CCl4

It implies that 0.209moles of CHCl3 will also give 0.209mol of CCl4

Mass of CCl4 formed = moles× molar mass= 0.209×154= 32.186g

6 0

3 years ago

Filtration, or screening, is one way to separate certain mixtures, as shown in the image. Which of these mixtures could be most

erastovalidia [21]

Answer: D

Explanation:

3 0

3 years ago

The half life for the decay of carbon-14 is 5.73 x 10 years. Suppose the activity due to the radioactive decay of the carbon-14

Elena-2011 [213]

Answer:

Age of the atifact is $4.2\times 10^{2}$ years

Explanation:

For first -order radioactive decay- $A_{t}=A_{0}(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}$
$A_{t}$ represents activity of radioactive nuclide after t time, $A_{0}$ represents initial activity of radioactive nuclide and $t_{\frac{1}{2}}$ represents half-life
Here, $A_{t}=19Bq$ , $A_{0}=20Bq$ and $t_{\frac{1}{2}}=5.73\times 10^{3}years$