lf the internal energy of the system decrease, then what can be conclude about the heat and the work done? A, Heat is added to t
1 answer:
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Given parameters:
Speed of car = 50m/s
Time of travel = 5minutes (300s)
Unknown;
Distance of travel = ?
To solve this problem, we need to understand how speed relates with distance and time.
Speed is a physical quantity. It is the distance traveled divided by time taken.
Speed =
So,
Distance = speed x time
Input the parameters and solve for the distance;
Distance = 50m/s x 300s
Distance = 15000m
The distance covered during this time interval and speed is 15000m
Answer:
Average speed of car will be 48 km/hr
Explanation:
Let the total distance is 2d
It is given that first half of the distance car travels with a speed of 40 km/hr
So time taken to cover half of the distance
Second half of the distance is covered with a 60 km/hr
So time taken to cover second half of the distance
So total time to cover 2d distance
Average speed is the ratio of total distance to total time
So average speed
So average speed of car will be 48 km/hr
Answer:
(a) The time the ball stays in the air is approximately 4.66 seconds
(b) The distance from the cannon at which the ball will hit the ground is approximately 83.18 meters
(c) The maximum altitude of the ball is approximately 26.62 m
Explanation:
The given parameters of the question are;
The initial velocity at which a baseball cannon fires balls, u = 29 m/s
The angle at which the cannon is tilted, θ = 52°
(a) The time duration the ball stays in the air is given by the time of flight of the projected ball as follows;
Where;
t = The time it takes the baseball to reach maximum height
2·t = The total time of flight = The time the ball stays in the air
θ = The angle at which the ball is tilted = 52°
g = The acceleration due to gravity ≈ 9.81 m/s²
u = The initial velocity = 29 m/s
Therefore, we have;
The time the ball stays in the air, 2·t ≈ 4.66 seconds
(b) The distance from the cannon at which the ball will hit the ground is given by the horizontal range, 'R', of the projectile as follows;
∴ The distance from the cannon at which the ball will hit the ground = R
The distance from the cannon at which the ball will hit the ground = R ≈ 83.18 meters
(c) The maximum altitude of the ball is equal to the maximum height reached by the ball, H, which is given as follows;
Therefore, we have;
The maximum altitude of the ball ≈ 26.62 m