Answer:
pH = 2.69
Explanation:
The complete question is:<em> An analytical chemist is titrating 182.2 mL of a 1.200 M solution of nitrous acid (HNO2) with a solution of 0.8400 M KOH. The pKa of nitrous acid is 3.35. Calculate the pH of the acid solution after the chemist has added 46.44 mL of the KOH solution to it.</em>
<em />
The reaction of HNO₂ with KOH is:
HNO₂ + KOH → NO₂⁻ + H₂O + K⁺
Moles of HNO₂ and KOH that react are:
HNO₂ = 0.1822L × (1.200mol / L) = <em>0.21864 moles HNO₂</em>
KOH = 0.04644L × (0.8400mol / L) = <em>0.0390 moles KOH</em>
That means after the reaction, moles of HNO₂ and NO₂⁻ after the reaction are:
NO₂⁻ = 0.03900 moles KOH = moles NO₂⁻
HNO₂ = 0.21864 moles HNO₂ - 0.03900 moles = 0.17964 moles HNO₂
It is possible to find the pH of this buffer (<em>Mixture of a weak acid, HNO₂ with the conjugate base, NO₂⁻), </em>using H-H equation for this system:
pH = pKa + log₁₀ [NO₂⁻] / [HNO₂]
pH = 3.35 + log₁₀ [0.03900mol] / [0.17964mol]
<h3>pH = 2.69</h3>
Answer:
Explanation:
From the sorensen equation; pH = -Log[H+]
2.7 = -Log[H+]
H+ = 10^-2.7
H+ = 0.001995M = Hydrogen ion concentration
Basically, the more the charges, the higher the hydrogen ion concentration stand vice versa. +2 has the highest concentration.
Answer:
62.15 m (squared)
Explanation:
We know that the Area of the square is 5.5 x 4= 22
so 90 degree to 30 degree is divide by 3
so u divide 22 by 3 and get 7.3 wich is the semi circle thing
now 7.3 x 5.5 = 40.15
22 + 40.15 = 62.15 m (squared)
Look im not really sure but I think this is the answer
<em><u>Please mark as brainliest</u></em>
Have a great day, be safe and healthy
Thank u
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