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postnew [5]
3 years ago
9

Which statement describes how a basic coffee cup calorimeter works?

Chemistry
1 answer:
pashok25 [27]3 years ago
3 0
Dooodeooceocowocowoo
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You have 50 ml of a complex mixture of weak acids that contains some HF (pKa = 3.18) and some HCN (pKa = 9.21). Which is larger,
telo118 [61]

Answer:

\frac{[F^{-}]}{[HF]} is larger

Explanation:

pK_{a}=-logK_{a} , where K_{a} is the acid dissociation constant.

For a monoprotic acid e.g. HA, K_{a}=\frac{[H^{+}][A^{-}]}{[HA]} and \frac{[A^{-}]}{[HA]}=\frac{K_{a}}{[H^{+}]}

So, clearly, higher the K_{a} value , lower will the the pK_{a}

In this mixture, at equilibrium, [H^{+}] will be constant.

K_{a} of HF is grater than K_{a} of HCN

Hence, (\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})

So, \frac{[F^{-}]}{[HF]} is larger

8 0
4 years ago
If a large chunk of sulfur is ground into powder, its mass will ___
pochemuha
Its mass will stay the same
8 0
3 years ago
I need help with this question, I don't get it
slamgirl [31]

Answer:

c.OF2

Explanation:

7 0
3 years ago
A pure liquid has a constant boiling point, but a liquid with a constant boiling point is not necessarily pure. Explain.
Brums [2.3K]

A pure liquid has a constant boiling point (at constant pressure). A change in boiling during distillation is an indication of impurity. The opposite, proposition, however, is not always true, and a constant boiling point does not necessarily mean that the liquid is pure.

This is because, at the boiling point, vapor and liquid are in equilibrium, and, if the composition of the vapor and liquid remains constant through the process, the temperature will also remain constant.

The boiling point can differ by location depending on pressure. Why does not a pure liquid in a distilling flask vaporize all at once whilst the boiling temperature is reached? Additional heat must be supplied for a phase change to occur.

Learn more about a boiling point here brainly.com/question/40140

#SPJ4

7 0
2 years ago
If 9 moles of P203 are formed, how many<br> moles of O2 reacted?
masha68 [24]
9 x 3 = 27
27 moles of O reacted
27 / 2 = 13.5 O2 reacted
round up to 14 moles of O2
3 0
2 years ago
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