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2 years ago

A pure liquid has a constant boiling point, but a liquid with a constant boiling point is not necessarily pure. Explain.

1 answer:

7 0

A pure liquid has a constant boiling point (at constant pressure). A change in boiling during distillation is an indication of impurity. The opposite, proposition, however, is not always true, and a constant boiling point does not necessarily mean that the liquid is pure.

This is because, at the boiling point, vapor and liquid are in equilibrium, and, if the composition of the vapor and liquid remains constant through the process, the temperature will also remain constant.

The boiling point can differ by location depending on pressure. Why does not a pure liquid in a distilling flask vaporize all at once whilst the boiling temperature is reached? Additional heat must be supplied for a phase change to occur.

Learn more about a boiling point here brainly.com/question/40140

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Which situation would cause the following equilibrium reaction to decrease the formation of the products? 2SO2 (g) + O2 (g) Two

vovangra [49]

The given equilibrium reaction is,

$2 SO_{2} (g) + O_{2}(g) 2 SO_{3} (g) + Energy$

The given reaction is exothermic. So, heat energy will be a product. Therefore, decreasing the temperature (heat energy) would lead to the formation of more products as when the amount of energy which is a product is reduced, there is more room for the products to form.

Increasing the pressure would shift the equilibrium towards that side which has least number of moles of the gaseous substance. Hence, here increasing the pressure would lead to the formation of more products by shifting the equilibrium towards the right side.

Decreasing the volume would make the equilibrium shift towards the least number of moles of the gaseous substance. So, here in this equilibrium decreasing the volume would lead to the formation of more products.

8 0

3 years ago

Read 2 more answers

how many moles of sodium hydroxide (NaOH) are required to completely neutralize 2 mol of nitric acid (HNO3)

Brut [27]

2 moles of sodium hydroxide will be needed.

<h3><u>Explanation</u>:</h3>

Sodium hydroxide is a compound which is a base and nitric acid is the acid. The formula of the nitric acid is HNO3 and that of sodium hydroxide is NaOH.

The reaction between them are

NaOH +HNO3 =NaNO3 +H2O.

So here we can see that 1 mole of sodium hydroxide reacts with 1 mole of nitric acid to produce 1 mole of sodium nitrate and 1 mole of water.

So for 2 moles of nitric acid, 2 moles of sodium hydroxide will be required.

6 0

3 years ago

What are the products of the reaction below?:<br> calcium chloride+ silver nitrate

WARRIOR [948]

Answer:

Calcium chloride react with silver nitrate to produce calcium nitrate and silver(I) chloride.

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2 years ago

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Describe how a new drilling site off the coast of Alaska would be analyzed.

sveta [45]

Answer:

Explanation:

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3 years ago

A sample of an unknown gas takes 371 s to diffuse through a porous plug at a given temperature.

blsea [12.9K]

Answer:

125.84 g/mol is the molar mass of the unknown gas.

Explanation:

Let the volume of the gases effusing out be V.

Effusion rate of the unknown gas = $R=\frac{V}{371 s}$

Effusion rate of the nitrogen gas = $r=\frac{V}{175 s}$

Molar mass of unknown gas = m

Mass of nitrogen gas = 28 g/mol

Graham's law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{R}{r}=\sqrt{\frac{28 g/mol}{M}}$

$\frac{\frac{V}{371 s}}{\frac{V}{175s}}=\sqrt{\frac{28 g/mol}{M}}$

$\frac{175 s}{371 s}=\sqrt{\frac{28 g/mol}{M}}$

$M=\frac{28 g/mol\times 371\times 371}{175\times 175}=125.84 g/mol$

125.84 g/mol is the molar mass of the unknown gas.

5 0

3 years ago