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GalinKa [24]
3 years ago
7

What pairs of numbers have a sum of 18 and the difference is 4

Mathematics
1 answer:
Mademuasel [1]3 years ago
6 0

Answer:

They are 7 and 11. 11 + 7 = 18, 11 - 7 = 4.

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A radio station had 205 tickets to a concert. They gave away 4 times as many tickets to listeners as to employees. How many tick
Citrus2011 [14]

Answer:

As per the statement: A radio station had 205 tickets to a concert. They gave away 4 times as many tickets to listeners as to employees.

⇒Let number of tickets Employees have x and Number of ticket Listeners  have 4x

It is also, given that a radio station had 205 ticket to a concert.

⇒ \text{Number of ticket Employees have} +\text{Number of ticket Listeners have} = 205

Then, substitute the given values we have;

4x + x = 205

Combine like terms, we have;

5x = 205

Divide both sides by 5 we have;

x = 41

Therefore, number of tickets did they give away to employees have 41 tickets



7 0
3 years ago
Please help me I don't get it and thanks!​
schepotkina [342]
(x + x² + 4x) 3

3(x) + 3(x²) + 3(4x)

3x + 3x² + 12x
4 0
3 years ago
How would you write the following expression as a single term? 3[2 ln(x-1) - lnx] + ln (x+1)
Elan Coil [88]

Apply the rule: n ln x = ln x^{n}

3[2 ln(x-1) - lnx] + ln(x+1)=3[ln(x-1)^{2} - lnx ] + ln(x+1)

Apply the rule : log a - log b = log \frac{a}{b}

3[2 ln(x-1) - lnx] + ln(x+1)=3ln\frac{(x-1)^{2} }{x} + ln(x+1)

Apply the rule: n ln x = ln x^{n}

3[ln (x-1)^{2} -ln x]+ln (x+1)= ln \frac{(x-1)^{6} }{x^{3} } +log(x+1)

Finally, apply the rule: log a + log b = log ab

3[ln(x-1)^{2} -ln x]+log(x+1)=ln\frac{(x-1)^{6}(x+1) }{x^{3} }

3 0
3 years ago
How do you do these questions?
algol [13]

Answer:

-x¹⁴ / 5040

-½ < x < ½

Step-by-step explanation:

f(x) = e^(-x²)

The Taylor series for eˣ centered at 0 is:

eˣ = ∑ (1/n!) xⁿ

Substitute -x²:

e^(-x²) = ∑ (1/n!) (-x²)ⁿ

e^(-x²) = ∑ (1/n!) (-1)ⁿ x²ⁿ

The 14th degree term occurs at n=7.

(1/7!) (-1)⁷ x¹⁴

-x¹⁴ / 5040

ln(1 + x) = ∑ₙ₌₁°° (-1)ⁿ⁺¹ xⁿ / n

If we substitute 4x²:

ln(1 + 4x²) = ∑ₙ₌₁°° (-1)ⁿ⁺¹ (4x²)ⁿ / n

Using ratio test:

lim(n→∞)│aₙ₊₁ / aₙ│< 1

lim(n→∞)│[(-1)ⁿ⁺² (4x²)ⁿ⁺¹ / (n+1)] / [(-1)ⁿ⁺¹ (4x²)ⁿ / n]│< 1

lim(n→∞)│-1 (4x²) n / (n+1)│< 1

4x² < 1

x² < ¼

-½ < x < ½

7 0
3 years ago
WILL GIVE BRAINLIEST PLEASE HELP
Debora [2.8K]

Answer:

the 3 one is the correct answer

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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