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3 years ago

What pairs of numbers have a sum of 18 and the difference is 4

Mathematics

1 answer:

Mademuasel [1]3 years ago

6 0

Answer:

They are 7 and 11. 11 + 7 = 18, 11 - 7 = 4.

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Factor x3 + x2 + x + 1 by grouping. What is the resulting expression? (x2)(x + 1) (x2 + 1)(x) (x2 + 1)(x + 1) (x3 + 1)(x + 1)

yanalaym [24]

Answer : $(x^2 + 1)( x + 1)$

Factor $x^3 + x^2 + x + 1$ by grouping

We group first two terms and last two terms

$(x^3 + x^2)+( x + 1)$

Now we take out GCF from each group

GCF of $(x^3 + x^2)$ is x^2

GCF of $+( x + 1)$ is 1

$(x^3 + x^2) +( x + 1)$

$x^2(x + 1) +1( x + 1)$

Now we factor out x+1 that is in common

$(x^2 + 1)( x + 1)$

6 0

4 years ago

Read 2 more answers

Please help me with these please.

Charra [1.4K]

6. Answer: y = 5x - 11

<u>Step-by-step explanation:</u>

Parallel means "same slope". y = 5x - 2 is in the form y = mx + b,

so the slope (m) = 5

Next, input the point (x₁, y₁ = 2, -1) and slope (m = 5) into the Point-Slope formula:

y - y₁ = m(x - x₁)

y - (-1) = 5(x - 2)

y + 1 = 5x - 10

y = 5x - 11

*******************************************************************

7. Answer: $\bold{y = \dfrac{1}{3}x + 4}$

<u>Step-by-step explanation:</u>

Perpendicular means "opposite reciprocal slope". y = -3x + 7 is in the form y = mx + b, so slope (m) = -3 ⇒ m⊥ = $\frac{1}{3}$

Next, input the point (x₁, y₁ = 3, 5) and slope (m = $\frac{1}{3}$ ) into the Point-Slope formula:

y - y₁ = m(x - x₁)

$y - 5=\dfrac{1}{3}(x - 3)$

$y - 5 =\dfrac{1}{3}x - 1$

$y=\dfrac{1}{3}x + 4$

8 0

3 years ago

Find the cosine of ∠J.

Lelu [443]

Answer:

$\cos = \frac{base}{hypotenuse} = \\ \cos(j) = \frac{ \sqrt{29} }{ \sqrt{94} } = \sqrt{ \frac{29}{94} } \\ answer = \sqrt{ \frac{29}{94} }$

4 0

2 years ago

What is the solution to the equation One-half x + 3 = two-thirds x + 1? One-third Two-thirds 2 12

AnnZ [28]

Answer:x = 12

Step-by-step explanation:

The equation One-half x + 3 = two-thirds x + 1 is expressed as

x/2 + 3 = 2x/3 + 1

The first step would be to to find the lowest common multiple of the left hand side of the equation and the right hand side of the equation and multiply the left hand side of the equation and the right hand side of the equation by the lowest common multiple. The lowest common multiple is 6. Therefore,

x/2 × 6 + 3 × 6 = 2x/3 × 6 + 1 × 6

3x + 18 = 4x + 6

4x + 6 = 3x + 18

Subtracting 3x and 6 from the left hand side of the equation and the right hand side of the equation, it becomes

4x - 3x + 6 - 6 = 3x - 3x + 18 - 6

x = 12

5 0

3 years ago

Read 2 more answers

JKLM is a rhombus. KM is 6 and JL is 8. Find the perimeter of the rhombus. image of rhombus JKLM with diagonals JL and KM inters

VLD [36.1K]

If a quadrilateral is a rhombus then:

i) all its sides have equal length,

and

ii) the 2 diagonals are perpendicular and bisect each other.

The 2 diagonals of rhombus JKLM intersect at N.

Then m(MNJ)=90°, |JN|=4 and |NM|=3 units

thus, by the Pythagorean theorem,

$|MJ|= \sqrt{ 3^{2} + 4^{2} }= \sqrt{9+16}= \sqrt{25}=5$

The perimeter of the rhombus is 4*5 units=20 units.

Answer: 20 units

4 0

3 years ago