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Ber [7]
3 years ago
6

Factor the given polynomial completely \. If the polynomial cannot be factored, say that is prime. y^4+10y^3+16y^2

Mathematics
2 answers:
PolarNik [594]3 years ago
7 0

Answer:

y^4+10Y^3+16y^2=0

y^2(y^2+10y^1+16y^0)=0

y^2+10y+16=0

on doing. factors of 10y we get 8y+2y

y^2+8y+2y+16=0

y(y+8)+2(y+8)=0

(y+2)(y+8)=0

1.y+8=0

y=-8

2.y+2=0

y=-2

hence y =(-8,-2)

Svetach [21]3 years ago
4 0
I took out the greatest common factor, which is y^2 and factored from there
You’ll end up with y^2(y+2)(y+8)
Here’s my work :)

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Alexandra [31]

Answer:

x = 135(being  \: opposite \: angles \: of \: a \: paralleogram)

Step-by-step explanation:

x =135(being opposite angles of a parallelogram)

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2 years ago
What is the value of z? <br> 4z+3=8
Anika [276]

Answer:

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Step-by-step explanation:

7 0
3 years ago
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When the outliers are removed, how does the mean change? (2 points) dot plot with 1 on 50, 1 on 76, 1 on 78, 2 on 79, 1 on 80, 1
777dan777 [17]

Answer:

Answer: The mean increases by 3

Step-by-step explanation:

The original data set is 

{50, 76, 78, 79, 79, 80, 81, 82, 82, 83}

The outlier is 50 because it is not near the group of values from 76 to 83 which is where the main cluster is.

The original mean is M = (50+76+78+79+79+80+81+82+82+83)/10 = 77

If we take out the outlier 50, the new mean is N = (76+78+79+79+80+81+82+82+83)/9 = 80

So in summary so far

old mean = M = 77

new mean = N = 80

The difference in values is N-M = 80-77 = 3

So that's why the mean increases by 3

8 0
3 years ago
¿Cuántos quilómetros recorrerá una locomotora en 5 horas, si marcha a una velocidad de 82 kilómetros
kicyunya [14]

Step-by-step explanation:

Datos;

una locomotora

recorre 5 horas

a una velocidad de 82 km/h

Se asume que la locomotora lleva un movimiento rectilíneo uniforme.

Su recorrido esta descrito por la siguiente ecuación de posición;

x = x₀+ v · t

x-x₀ = d = v · t

siendo;

d = distancia recorrida

v = 82 km/h

t = 5 horas

Sustituir:

d = (82)(5)

d = 410 km

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6 0
3 years ago
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Shtirlitz [24]
1, 4, and 5:) hope this helps.
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2 years ago
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