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timofeeve [1]
3 years ago
6

Three people are trying to move a box. Which set of forces will result in a net

Physics
1 answer:
maksim [4K]3 years ago
7 0

<u>Answer </u><u>:</u><u>-</u>

The person who is exerting 55N will move the  box 20N to the right (<u>option B</u>).

<u>Reason :-</u>

  • The total force by the two people in the left side is .. 17 N + 16N  = 33N.
  • So, the net force acting on the box is, 55N - 33N = <u>20N</u>.
  • The box will move towards the <u>right</u> because greater force is acting there.

<em>Check </em><em>the </em><em>attached</em><em> </em><em>pictures.</em>

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A 5g block rests on a rough horizontal table a rope attached to the block is pulled with a force of 11N to the left as a result
mr Goodwill [35]

<u>Complete Question:</u>

A 5 g block rests on a rough horizontal table. A rope is attached to the block and is pulled with a force of 11 N to the left. As a result, the block accelerates at 2 m/s^2. What is the kinetic friction between the block and the table?

<u>Correct Answer:</u>

The kinetic frictional force between the block and the rough surface is 10.99 N towards the right side.

F_{net} = - 0.01 N is the resulting net force causing an acceleration of 2\ m/s^2 to the left

<u>Explanation:</u>

According to the first law of motion by Newton, any object can be moved only when an unbalanced force acts on the object. As the block is placed on a rough horizontal table, then the applied force should be greater than the kinetic frictional force between the object and the rough surface, in order to move that block.

So, it is known that the net force acting on the block will be the difference between the force acting on the object due to the rope and the frictional force acting on the object.

F_{net} = F_{rope} -F_{friction}

So, the force acting on the block due to rope is given as 11 N. The net force should be equal to the product of mass and acceleration of the object, as per Newton's second law of motion. As the mass of the block is 5 g and the acceleration is given as 2\ m/s^2.

F_{net} = Mass * Acceleration = \frac{5}{1000} * -2  = -0.01 N

Since, the net force and the force due to rope is acting opposite to the gravitational force ,

-0.01 = -11 - Frictional force

Frictional force = -11 + 0.01 = -10.99 N

Thus, the kinetic frictional force between the block and the rough surface is 10.99 N towards the right side.

F_{net} = - 0.01 N is the resulting net force causing an acceleration of 2\ m/s^2 to the left

7 0
3 years ago
What is tan(61)?<br> А. 1.80<br> B. 0.49<br> C. 0.61<br> D. 0.87
pav-90 [236]

Answer:

The answer of tan(61) is:

A= 1.80

7 0
3 years ago
A 1.5 kg ball is thrown upward at 10 m/s. What is its velocity when it is 2 m above the release point?
Anestetic [448]

Answer:

7.75m/s or 2\sqrt{15}m/s

Explanation:

m = 1.5kg

u= 10m/s

s = 2m

a = 10m/s^{2}

v = ?

acceleration due to gravity is negative when an object is going up because the force of gravity reduces the speed of the object

using the formula ;

v^{2} = u^{2} - 2as since the object is moving upwards (negative acceleration)

= 100 - 2(10)(2)

100 - 40

v^{2} = 60

v = \sqrt{60}

= 7.75m/s

5 0
3 years ago
Plate Tectonics Lab: Snicker’s Science
Marizza181 [45]

Answer:

sup

Explanation:

8 0
3 years ago
Read 2 more answers
Can you please help me with these physics displacement questions? If you can only do one, that is okay
Brut [27]

#3).  Your drawing in the lower right corner is correct.  You're headed down the right road, but ran out of gas and just stopped.

Radius of the circle = 1.5 km

Circumference of the whole circle = (2·π·radius) = 9.42 km

Distance = 3/4 of the way around it = 7.07 km .

Displacement = the straight line from the West point to the North point.  The straight-line length is 2.12 km; the straight-line direction from start to finish is Northeast (45°).  I'll let you figure out why these numbers.

#4).  What if you walk 1 mile East and then 1 mile West ?  You got a good workout, and you're back home where you started !  Your distance is 2 miles, and your displacement is zero.

The whale had a good workout too.  She swam (6.9 + 1.8 + 3.7) = 12.4 km.  She's sweating and tired.  Her total distance during that workout is 12.4 km.  

Her displacement is the line from start-point to end-point.  How she got there doesn't matter, so swimming 1 km East and then swimming 1 km West cancel out, and have no effect on the displacement.

(6.9E + 1.8W + 3.7E)  =  (10.6 E) + (1.8 W) . . . That adds up to  8.8 East !  That's where she ends up.  That's her displacement ... 8.8 km East of where she started.  Since we're only talking about displacement, we don't care HOW she got there.  She might have been swimming big 20-km circles all day.  We don't know.  All we know is that she ended up 8.8 km East of where she started.


7 0
3 years ago
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