The equation for power is P=VI, we can then rearrange V=IR and substitute I into the equation, this gets us V/R=I. Thus we get P=V^2/R
Next we convert kΩ to Ω. This tells us the resistor in Ω is 5600Ω.
Finally, plug into equation, we get P = (5V^2)/5600Ω.
P = 0.0044642857W
Hope this helps!
Because there is a gravitational force affecting the orbit of the far outer planets. (Neptune, Uranus)
Answer:
500 N
Explanation:
Given that,
The upward force is 800 N and the downward forces are 400 N, 500 N, 400 N.
At equilibrium, the upward forces will become equal to the downward forces. Let the reading in the right hand scale.
x + 800 = 400 + 500 + 400
x + 800 = 1300
x = 1300 - 800
= 500 N
So, the reading in the right hand scale is 500 N.
Running that process in a power plant would not only eliminate the
danger of a core meltdown, it would also pretty much eliminate the
possibility of getting any nuclear power out of the plant.
The understanding behind your question is correct . . . Neutrons coming
out of one fission go on to get absorbed in other nuclei, and cause the
other ones to fiss. BUT . . . NOT every free neutron whizzing around in
the core material gets absorbed. Some of them enter another nucleus
and immediately get spit out. And some of them never get near another
nucleus at all. Of all the neutrons produced in one fission, only some
percentage go on to stimulate another one. So if each fission produced
only one neutron, then the whole process would completely run out of gas
in some amount if time, as the number of free neutrons dwindled and shrank.
