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Elena L [17]
3 years ago
11

Why is it important to use the correct number of significant digits when

Physics
1 answer:
Pani-rosa [81]3 years ago
5 0

A. To show how precise your measurements were

Explanation:

It is important to use the correct number of significant digits when reporting the results of an experiment because they show how precise measurement are.

  • Precision is the ability to reproduce a particular set of results in an experiment.
  • Every instrument have their precision level.
  • The precision levels shows to what extent the values obtained can be trusted..
  • Significant figures are not only important in recording measurements, they are also needed for calculations in science.

Learn more:

Significant figures brainly.com/question/4967602

#learnwithBrainly

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A 128 gram Radium-226 sample with a half-life of 2.25 billion years is found. How many grams will remain after two half-lives?
Bess [88]

Answer:

Option B. 32 g

Explanation:

From the question given above, the following data were obtained:

Original amount (N₀) = 128 g

Half-life (t½) = 2.25 billion years

Number of half-lives (n) = 2

Amount remaining (N) =?

The amount of 128 gram of Radium-226 that will remain after 2 half-lives has elapsed can be obtained as followb

N = 1/2ⁿ × N₀

N = 1/2² × 128

N = 1/4 × 128

N = 0.25 × 128

N = 32 g

Therefore, 32g of the sample will remain.

8 0
2 years ago
a book is sitting still on your desk. are the forces acting on the book balanced or unbalanced? explain.
GrogVix [38]
<span>They are balanced. If the forces were not balanced the book would move*. In this example, the downward force of gravity on the book is counterbalanced by the upthrust of the desk. </span>
8 0
3 years ago
Read 2 more answers
When she rides her bike, she gets to her first classroom building 36 minutes faster than when she walks. Of her average walking
postnew [5]

Answer:

d=2.4\ miles

Explanation:

Given:

  • average walking speed, v_w=3\ mph
  • average biking speed, v_b=12\ mph

<u>According to given condition:</u>

t_w=t_b+\frac{36}{60}

where:

t_w= time taken to reach the building by walking

t_b= time taken to reach the building by biking

We know that,

\rm time=\frac{distance}{speed}

so,

\frac{d}{v_w} =\frac{d}{v_b} +\frac{36}{60}

\frac{d}{3}=\frac{d}{12} +\frac{3}{5}

d=2.4\ miles

7 0
3 years ago
Read 2 more answers
Two objects, with different sizes, masses, and temperatures, are placed in thermal contact. in which direction does the energy t
s344n2d4d5 [400]
<span>(c) energy travels from the object at higher temperature
to the object at lower temperature.

Size and mass have no effect.</span>
3 0
3 years ago
Find the magnitude of the electric field due to a charged ring of radius "a" and total charge "Q", at a point on the ring axis a
34kurt

Answer:

E=\frac{KQ}{2\sqrt 2a^2}

Explanation:

We are given that

Charge on ring= Q

Radius of ring=a

We have to find the magnitude of electric filed on the axis at distance a from the ring's center.

We know that the electric field at distance x from the center of ring of radius R is given by

E=\frac{kQx}{(R^2+x^2)^{\frac{3}{2}}}

Substitute x=a and R=a

Then, we get

E=\frac{KQa}{(a^2+a^2)^{\frac{3}{2}}}

E=\frac{KQa}{(2a^2)^{\frac{3}{2}}}

E=\frac{KQa}{2\sqrt 2a^3}

E=\frac{KQ}{2\sqrt 2a^2}

Where K=9\times 10^9 Nm^2/C^2

Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center=\frac{KQ}{2\sqrt 2a^2}

4 0
3 years ago
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