Because a variable is an important stratagy of science
<span>First let's find the acceleration required in the barrel to speed the ball up from 0 to 83 m/s in a distance of 2.17 m. We know the force the cannon exerts on the cannonball is 20000 N; if we can find this acceleration then we can use F = ma to find the mass.
We can find the acceleration using one of the kinematic equations of motion. We have:
u = initial speed = 0 m/s
v = final speed = v0 = 83 m/s
d = distance = 2.17 m
a = acceleration = ?
v² = u² + 2ad. Since u = 0, this reduces to v² = 2ad and rearranges to a = v²/2d = 83²/2*2.17 = 83²/4.34 = 1587.327 m/s².
Now F = ma, so m = F/a = (20000N)/(1587.327 m/s²) = 12.6 kg.
For part 2, use the Range Equation:
If R is the horizontal distance the cannonball travels,
v = v0 = the initial velocity = 83 m/s
g = acceleration due to gravity - 9.8 m/s²
x the launch angle relative to the horizontal, then
R = (v²sin(2x))/g.
So R = (83²sin(2*37))/9.8
= (6889sin74)/9.8 = 676 m.
So the target ship is 676 m away.</span>
The x and y coordinates of the particle at this moment is (6x + 4.5y) m.
<h3>
Position of the particle </h3>
The position of the particle at any instant is determined from the velocity and acceleration of the particle as shown below.
v² = u² + 2as
where;
- v is the final velocity of the particle
- u is the initial velocity
- a is the acceleration of the particle
- s is the position of the particle
v² = 0 + 2as
v² = 2as
s = v²/2a
<h3>X and y - coordinates of the particle</h3>
Thus, the x and y coordinates of the particle at this moment is (6x + 4.5y) m.
Learn more about position of a particle here: brainly.com/question/2560794
Answer:
Work done, W =1520 J
Explanation:
We have,
The brakes on a bicycle apply 95 N of force to the wheels. When the brakes are applied, the bicycle comes to a stop in 16 m.
It is required to find the work done by the brakes on the wheels. We know that the product of force and displacement is equal to the work done. It is given by :
So, the work done by the brakes is 1520 J.