2 years ago

If a car has a momentum of 1000kgm/s and velocity of 500m/s, what is its mass

Physics

1 answer:

Dvinal [7]2 years ago

7 0

Answer:

hey u apply p=mv and 2 are given then calculate thirds value it's a simple do it

You might be interested in

Throughout the problem, take the speed of sound in air to be 343 m/s . Part A Consider a pipe of length 80.0 cm open at both end

White raven [17]

Answer:

the lowest frequency f of the sound wave is 214.375 Hz

Explanation:

The computation of the lowest frequency f of the sound wave is shown below;

Length = L= 80 cm

= 0.8 m

V = 343 m/s (sound speed in air )

Now

V1 = n V ÷ 2 L

= 1 × 343 ÷ 2 × 0.8

V1 = 214.375 Hz

Hence, the lowest frequency f of the sound wave is 214.375 Hz

We simply applied the above formula so that the correct value could come

And, the same is to be considered

6 0

3 years ago

Use the information and model to answer the following question.

olga_2 [115]

Answer:

Explanation:

7 0

2 years ago

Read 2 more answers

Determine in symbols an expression for the magnetic force exerted on the falling bar (and determine the direction of that force)

Katarina [22]

Answer:

magnetic force on falling Bar F = B*i*L*sin(90) = B*(B*L*v/R)*L = B^2*L^2*v/R

direction of the force is vertically upwards

Explanation:

8 0

3 years ago

Which sentence best explains the law of conservation of mass as applied to

drek231 [11]

Answer:

A. The amount of mass changes only slightly during a chemical

reaction.

3 0

2 years ago

What current flows through a 2.54cm diameter rod of pure silicon that is 20cm long when 1000V is applied?

vfiekz [6]

Answer: $0.0039\ A$

Explanation:

Given

Diameter of the rod $d=2.54\ cm$

length of rod is $l=20\ cm$

Resistivity of silicon is $\rho=6.4\times 10^2\ \Omega-m$

cross-section of the rod $A$

$\Rightarrow A=\dfrac{\pi d^2}{4}\\\\\Rightarrow A=\dfrac{3.142\times 2.54^2\times 10^{-4}}{4}\\\\\Rightarrow A=5.067\times 10^{-4}\ m^2$

Resistance of rod is R

$\Rightarrow R=\dfrac{\rho l}{A}$

$\Rightarrow R=\dfrac{640\times 0.20}{5.067\times 10^{-4}}\\\\\Rightarrow R=25.26\times 10^4\ \Omega$

Current is given by

$\Rightarrow I=\dfrac{V}{R}\\\\\Rightarrow I=\dfrac{1000}{25.26\times 10^4}\\\\\Rightarrow I=0.0039\ A$

3 0

2 years ago