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Komok [63]
3 years ago
10

I think 40 is the answer but i need confirmation

Physics
2 answers:
guapka [62]3 years ago
6 0
I'd say we can't tell from the information given in the picture. We don't know what's on the right side of the right pulley.

If the rope that goes under the right pulley goes up the right side of it to, say, another hook in the ceiling, then there are two ropes holding the right pulley and the 40N weight. The tension on each side of the right pulley is 20N, and W is 20N.

But we don't know ... we can't see what happens to the rope when it goes under the right pulley.
NNADVOKAT [17]3 years ago
3 0
You’re right, bc I’m the question it says the pulley is at equilibrium
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Calculate the percentage increase in speed of the cyclist when the power output changes from 200 W to 300 W.
Rom4ik [11]

Answer:

<em>50%</em>

Explanation:

Given

Initial power = 200W

Final power = 300W

Increment = 300 - 200 = 100W

percentage increase = increment/initial power * 100

percentage increase = 100/200 * 100%

percentage increase = 0.5 * 100

percentage increase = 50%

<em>Hence the percentage increase in speed is 50%</em>

6 0
3 years ago
How much heat do you need to raise the temperature of 150 g of oxygen from -30c to -15c?
Naddika [18.5K]
The amount of heat needed to raise the temperature of a substance by \Delta T is given by
Q=m C_s \Delta T
where
m is the mass of the substance
Cs is its specific heat capacity
\Delta T is the increase in temperature

For oxygen, the specific heat capacity is approximately 
C_s = 0.92 J/(g K)
The variation of temperature for the sample in our problem is 
\Delta T= -15^{\circ}C-(-30^{\circ} C)=+15^{\circ}C=15 K
while the mass is m=150 g, so the amount of heat needed is
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4 0
3 years ago
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A 1000.0 kg truck accelerates from 20.0 m/s to 25.0 m/s over a distance of 300.0 m. What is the average net force on the truck?
choli [55]

Answer:

The average net force on the truck is 375 Newtons.

Explanation:

Using Newton's 3rd equation of motion, we have :

v^{2} - u^{2} = 2×a×s

where, v = final velocity = 25 m/s

u = initial velocity = 20 m/s

a = acceleration

s = distance traveled = 300 m

Using these values in the above equation, we get acceleration = 0.375 m/s^{2}

Using Newton's second law, we have:

F=m×a

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a= acceleration = 0.375 m/s^{2}

Putting values we have F=375 N

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On Earth ...

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Weight = 9.8 Newtons

8 0
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