<h2>
Speed of the race car at the end of the run is 97.57 m/s</h2>
Explanation:
We have equation of motion v² = u² + 2as
Initial velocity, u = 0 m/s
Acceleration, a = 11.9 m/s²
Final velocity, v = ?
Displacement,s = 400 m
Substituting
v² = u² + 2as
v² = 0² + 2 x 11.9 x 400
v = 97.57 m /s
Speed of the race car at the end of the run is 97.57 m/s
To answer this problem, we can use the lower and upper limits altogether of the dimensions given. In this case, the minimum area is the product of 22.2 cm and 8.3 cm that is equal to 184.26 cm2 while the maximum area is equal to 22.6 cm times 8.5 cm equal to 192. 1 cm2. Plainly, 22.4 cm times 8.4 cm is equal to 188.16 cm2. The area is equal then to 188.16 +- 3.9 cm2
Answer:
-7500 N
Explanation:
v₀ = 108 km/h = 30 m/s
v = 0 m/s
t = 4 s
a = Δv / Δt
a = (0 m/s − 30 m/s) / 4 s
a = -7.5 m/s²
F = ma
F = (1000 kg) (-7.5 m/s²)
F = -7500 N
Average velocity = Total Displacement / Total time taken
Total displacement is the distance from starting to end point.
35km west then 90km north. When you will draw this and connect starting to end point. You will get a right angled triangle.
So displacement =

= 96.56 km
So, Total displacement = 96.56 km
So, Average Velocity = 96.56 / 2 = 48.28 km/hr
Electron Cloud and nuclei