The volume generated by rotating the given region 
about OC is 
<h3>
Washer method</h3>
Because the given region () has a look like a washer, we will apply the washer method to find the volume generated by rotating the given region about the specific line.
solution
We first find the value of x and y
![v= \pi \int\limits^2_o= [\frac{y^{2} }{4} - \frac{y^{8} }{2^{8} }} ] dy](https://tex.z-dn.net/?f=v%3D%20%5Cpi%20%5Cint%5Climits%5E2_o%3D%20%5B%5Cfrac%7By%5E%7B2%7D%20%7D%7B4%7D%20-%20%5Cfrac%7By%5E%7B8%7D%20%7D%7B2%5E%7B8%7D%20%7D%7D%20%20%5D%20dy)
![v= \pi [\int\limits^2_o {\frac{y^{2} }{4} } \, dy - \int\limits^2_o {\frac{y}{2^{8} } ^{8} } \, dy ]](https://tex.z-dn.net/?f=v%3D%20%5Cpi%20%5B%5Cint%5Climits%5E2_o%20%7B%5Cfrac%7By%5E%7B2%7D%20%7D%7B4%7D%20%7D%20%5C%2C%20dy%20-%20%5Cint%5Climits%5E2_o%20%7B%5Cfrac%7By%7D%7B2%5E%7B8%7D%20%7D%20%5E%7B8%7D%20%7D%20%5C%2C%20dy%20%5D)
![v=\pi [\frac{1}{4} \frac{y^{3} }{3} \int\limits^2_0 - \frac{1}{2^{8} } \frac{y^{g} }{g} \int\limits^2_o\\v= \pi [\frac{1}{12} (2^{3} -0)-\frac{1}{2^{8}*9 } (2^{g} -0)]\\v= \pi [\frac{2}{3} -\frac{2}{g} ]\\v= \frac{4}{g} \pi](https://tex.z-dn.net/?f=v%3D%5Cpi%20%5B%5Cfrac%7B1%7D%7B4%7D%20%5Cfrac%7By%5E%7B3%7D%20%7D%7B3%7D%20%20%5Cint%5Climits%5E2_0%20-%20%5Cfrac%7B1%7D%7B2%5E%7B8%7D%20%7D%20%20%5Cfrac%7By%5E%7Bg%7D%20%7D%7Bg%7D%20%5Cint%5Climits%5E2_o%5C%5Cv%3D%20%5Cpi%20%5B%5Cfrac%7B1%7D%7B12%7D%20%282%5E%7B3%7D%20-0%29-%5Cfrac%7B1%7D%7B2%5E%7B8%7D%2A9%20%7D%20%282%5E%7Bg%7D%20-0%29%5D%5C%5Cv%3D%20%5Cpi%20%5B%5Cfrac%7B2%7D%7B3%7D%20-%5Cfrac%7B2%7D%7Bg%7D%20%5D%5C%5Cv%3D%20%5Cfrac%7B4%7D%7Bg%7D%20%5Cpi)
A similar question about finding the volume generated by a given region is answered here: brainly.com/question/3455095
Henry has completed 40% of his work, leaving him with a remaining 60%.
What you do is divide 20 by 50 and your answer is .4, move the decimal two places to the right to get your percent, 40. Then subtract it out of 100 and you get the remaining 60%, which essentially is your answer.
Answer:
Mimi is 15.
Step-by-step explanation:
Set up two equations, and solve by elimination.
2(m+5) = d+5
- 3(m-5) = d-5
_____________
2(m+5) - 3(m-5) = 10
2m + 10 - 3m + 15 = 10
-m + 25 = 10
-m = -15
<u>m = 15</u>
Plug this back in to get dad's age.
2(m+5) = d+5
2(15+5) = d + 5
2(20) = d + 5
40 = d + 5
<u>d = 35</u>
<u></u>
Answer:
Given:
I usually walk from home to work. This morning, I walked for 10 minutes until I was halfway to work.
I then realized that I would be late if I kept walking.
I ran the rest of the way. I run twice as fast as I walk.
Find:
The number of minutes in total did it take me to get from home to work
Step-by-step explanation:
Had I kept walking, the second half of my trip would have taken 10 more minutes.
By doubling my speed for the second half of my trip,
I halved the amount of time it took me to finish.
So, the second half of my trip took 5 minutes, for a total trip time of 10+5 = 15 minutes.
The number of minutes in total did it take me to get from home to work is 15 minutes.
Answer:
Part A
20x + 25y = 210 --> D.
Part B
If jane purchased exactly 4 shirts she must have purchased Exactly ___ skirts. (round to the nearest tenth)
20*4 + 25y = 210 --> y = 5.2
is it possible for jane to purchase exactly 4 shirts? ____(yes or no)
no, because she can't buy 5.2 skirts.
