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kvasek [131]
2 years ago
14

Brainliest to correct !!!

Mathematics
1 answer:
dalvyx [7]2 years ago
4 0

I’m not sure if I am correct ,

Informally, each hour of overtime is like 2.5 hours of regular time, so 8 hours of overtime is like 8*2.5 = 20 hours of regular time.

So her $1470 earnings are for 40+20 = 60 hours of work.

Her regular hourly wage is 1470$/60=24.5 dollars

40(x)+8(2.5x)=1470
40x+20x=1470
60x=1470
X=1470/60
X=24.5 dollars

Answer =24.5$
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motikmotik

Answer:

22 rides happened in the hour.

Step-by-step explanation:

The way to solve this if by first dividing the 650 by the 30 then since the answer will be 21.6 that is basically like having 21 full rides then having one more ride a little over half full.

6 0
3 years ago
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3 0
2 years ago
Write each as a decimal. Round to the thousandths place.<br> 9) 78.4%<br> 10) 29%<br> Help
fomenos

Answer:

(a) 78.4\% = 0.784

(b) 29\% =0.290

Step-by-step explanation:

Required

As a decimal to nearest thousandth

Solving (a): 78.4%

78.4\%

Express as fraction

78.4\% = \frac{78.4}{100}

Solve fraction

78.4\% = 0.784 ----- This is already in thousandth place

Solving (b): 29%

29\%

Express as fraction

29\% =\frac{29}{100}

Solve fraction

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4 0
3 years ago
a scout meeting lasts 2 hours. if 36 minutes was spent on making dream catchers, what percentage of the meeting is left
Llana [10]

Answer:

70% of the meeting is left.

Step-by-step explanation:

Hi, to answer this question, first, we have to convert the hours to minutes.

Since 1 hour = 60 minutes

For 2 hours:

1 /60 = 2/x

x = 2 (60)

x = 120 minutes

So, a scout meeting last 120 minutes (2 hours)

36 minutes already spent.

120-36 = 84 minutes left

So, if 120 is the 100% of the meeting, for 84 minutes:

120/100 = 84/x

1.2 =84/x

x = 84/1.2

x = 70%

70% of the meeting is left.

8 0
3 years ago
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beks73 [17]

Answer:

\frac{2}{5}±\frac{\sqrt{17}}{5}

Step-by-step explanation:

(5x-2)^2=17 \\ 5x-2=±\sqrt{17} \\ 5x = 2 ± \sqrt{17}   \\ x=\frac{2}{5}± \frac{\sqrt{17}}{5}

Don't mind the ±

5 0
2 years ago
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