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3 years ago

Which units are used to measure both velocity and speed? Select three options

Chemistry

1 answer:

Ede4ka [16]3 years ago

8 0

Answer and Explanation:

The options aren't listed in your question, but here are some units that are regularly and normally used (in the classroom and in the outside world):

(The SI unit of distance and displacement is the meter. The SI unit of time is the second.)

Meters per Second (m/s)

kilometers per hour (km/hr)

kilometers per second (km/sec)

To find the average speed, you do distance divided by time.

To find the average velocity, you do the final position minus the initial position, divided by the final time minus the initial time.

#teamtrees #PAW (Plant And Water)

I hope this helps!

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Question

andreev551 [17]

Answer:

Sln

n=m/mr

n=25/100

n=0.25mole of Caco3

Malality =number of moles/volume (divided by number of moles both sides)

volume =Malality /number of moles

v=0.125/0.25

v=0.500L

I hope this help

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2 years ago

If a gas in a box with fixed volume has a pressure of 913 torr at 15 C, what temperature should the gas be heated to double the

algol13

700 mL hop it helps u ok

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3 years ago

A reaction mixture at 175 k initially contains 522 torr of no and 421 torr of o2. at equilibrium, the total pressure in the reac

zzz [600]

The chemical equation would be:

2NO(g) + O2(g) --> 2NO2 (g)

At equilibrium state, the partial pressure of the gases would be as follows : 

NO = 522 - 2x 

O2 = 421 - x 

NO2 = 2x 
- - - - - - - - - - - - -
943 - x = 748 

x = 195

Calculating for Kp,

Kp = (NO2)^2/ ((NO)^2 * (O2)) 

Kp = (2 * 195)^2/ ((522 - 2 * 195)^2 * (421 - 195)) 

Kp = 0.0386

4 0

3 years ago

How much water would I need to add to 700 mL of a 2.7 M KCl solution to make a 1.0 M solution?

geniusboy [140]

Answer:

$1190\ \text{mL}$

Explanation:

$M_1$ = Initial Concentration of KCl = 2.7 M

$V_1$ = Volume of KCl = 1 M

$M_2$ = Final concentration of KCl = 1 M

$V_2$ = Amount of water

We have the relation

$M_1V_1=M_2V_2\\\Rightarrow V_2=\dfrac{M_1V_1}{M_2}\\\Rightarrow V_2=\dfrac{2.7\times 700}{1}\\\Rightarrow V_2=1890\ \text{mL}$

The amount of water that is to be added is $1890-700=1190\ \text{mL}$ .

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2 years ago

5. Discuss the phenomena of sunrise and sunset seen on Earth and describe how they will be different from the perspective of out

Colt1911 [192]

Despite its appearance, air has a ‘thickness’ so when the sun is high in the sky the light travels through the air on a very much shorter path than when it is low on the horizon.

Imagine that air water and you are below the surface, the light from an overhead sun will be quite sharp and bright, but if lower in the sky it will have to travel through much more water to reach you, so will look less bright and sharp. It ma not seem the same, but the atmosphere is just like very thin water, and a low lying sun will be drastically reduced in strength, so all you will see is a sun with a shift to the red end of the spectrum as all the actinic part will be filtered away by that thicker atmosphere.

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2 years ago