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chubhunter [2.5K]
3 years ago
7

A reaction mixture at 175 k initially contains 522 torr of no and 421 torr of o2. at equilibrium, the total pressure in the reac

tion mixture is 748 torr. calculate kp at this temperature.
Chemistry
1 answer:
zzz [600]3 years ago
4 0
The chemical equation would be:

2NO(g) + O2(g) --> 2NO2 (g) 

<span>At equilibrium state, the partial pressure of the gases would be as follows : </span>

<span>NO = 522 - 2x </span>

<span>O2 = 421 - x </span>

<span>NO2 = 2x </span>
<span>- - - - - - - - - - - - -</span>
<span>943 - x = 748 </span>

<span>x = 195</span>

Calculating for Kp,

<span>Kp = (NO2)^2/ ((NO)^2 * (O2)) </span>

<span>Kp = (2 * 195)^2/ ((522 - 2 * 195)^2 * (421 - 195)) </span>

<span>Kp = 0.0386 </span>
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The answer to your question is 0.1595 mg of Oxygen

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Data

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Process

1.- Convert 336 mg to grams

                           1000 mg ----------------- 1 g

                            336 mg  ----------------  x

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