Question

How much water would I need to add to 700 mL of a 2.7 M KCl solution to make a 1.0 M solution?

Answer 1

Answer:

$1190\ \text{mL}$

Explanation:

$M_1$ = Initial Concentration of KCl = 2.7 M

$V_1$ = Volume of KCl = 1 M

$M_2$ = Final concentration of KCl = 1 M

$V_2$ = Amount of water

We have the relation

$M_1V_1=M_2V_2\\\Rightarrow V_2=\dfrac{M_1V_1}{M_2}\\\Rightarrow V_2=\dfrac{2.7\times 700}{1}\\\Rightarrow V_2=1890\ \text{mL}$

The amount of water that is to be added is $1890-700=1190\ \text{mL}$.