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Aleks04 [339]
3 years ago
10

Consider the combustion of glucose: c6h12o6(s) + 6 o2(g) ←→ 6 co2(g) + 6 h2o(g) ∆h = −2, 800 kj/mol which condition i) adding mo

re carbon dioxide ii) performing the reaction in a hotter environment iii) decreasing the pressure of the system would result in the production of additional water vapor?
Chemistry
1 answer:
Verizon [17]3 years ago
6 0
The answer is iii) decreasing the pressure of the system. When the pressure is decreased, the equilibrium will shift to the right because it has 12 moles of gas which is greater than the number of moles of gas on the left side, which is 6 moles. Equilibrium shifting to the side that exerts greater pressure is favored to offset the decrease in pressure.
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What caused our solar system to form by pulling together gases and dust in a nebula?​
Furkat [3]
I’m pretty sure it’s gravity man
5 0
2 years ago
g If you have three identical containers (same volume) at the same temperature and pressure, each with a different gas. Containe
vekshin1

Answer:

<em>The three gases, in the three identical containers, will all have the same number of molecules</em>

Explanation:

If these three gases (Helium He, Neon Ne, and Oxygen O_{2}) are all contained in separate identical containers with the same volume. And they are all stored at the same temperature, and pressure. Then, they'll all contain the same number of molecules. This is in line with Avogadro's law which states that "Equal volume of all gases, at the same temperature and pressure, have the same number of molecules."

6 0
3 years ago
Write chemical equation for the following reactions. Indicate physical states and write net ionic equations. If no reaction indi
iren [92.7K]

There is no reaction.

<em>Molecular equation :</em>

K₂CO₃(aq) + 2NH₄Cl(aq) ⟶ 2KCl(aq) + (NH₄)₂CO₃(aq)

<em>Ionic equation :</em>

2K⁺(aq) + CO₃²⁻(aq) + 2NH₄⁺(aq) +2Cl⁻(aq) ⟶ 2K⁺(aq) + 2Cl⁻(aq) + 2NH₄⁺(aq) + CO₃²⁻(aq)

<em>Net ionic equation :</em>

Cancel all ions that appear on both sides of the reaction arrow (underlined).

<u>2K⁺(aq)</u> + <u>CO₃²⁻(aq)</u> + <u>2NH₄⁺(aq</u>) +<u>2Cl⁻(aq)</u> ⟶ <u>2K⁺(aq)</u> + <u>2Cl⁻(aq</u>) + <u>2NH₄⁺(aq)</u> + <u>CO₃²⁻(aq)</u>

<em>All ions cancel</em>. There is no net ionic equation.

7 0
4 years ago
The sample concentration was measured at 50mg/ml. The loading concentration needs to be 10mg/ml. The final volume needs to be 25
Svet_ta [14]

Answer:

a)  V_1=5ul

b)  v=20ul

Explanation:

From the question we are told that:

initial Concentration C_1=50mg/ml

Final Concentration C_2=10mg/ml

Final volume needs V_2 =25ul

Generally the equation for Volume is mathematically given by

C_1V_1=C_2V_2

V_1=\frac{C_1V_1}{C_2}

V_1=\frac{10*25}{50}

V_1=5ul

Therefore

The volume of buffer needed is

v=V_2-V_1\\\\v=25-5

v=20ul

3 0
3 years ago
Suppose a 5.00 l sample of o2 at a given temperature and pressure contains 1.08
arsen [322]
Missing question: <span>A 5.00 L sample of O2 at a given temperature and pressure contains a 1.08x10^23 molecules. How many molecules would be contained in each of the following at the same temperature and pressure? </span>
a) 5.00 L H2.
<span>b) 5.00 L CO2.
Use </span>Avogadro's Law: The Volume Amount Law: <span>equal </span>volumes<span> of all gases, at the same temperature and pressure, have the same </span>number<span> of molecules. Because hydrogen and carbon(IV) oxide are gases, number of molecules are the same as number of oxygen molecules, so:
a) N(H</span>₂) = 1.08·10²³.
b) N(CO₂) = 1.08·10²³

5 0
3 years ago
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