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3 years ago

15

vicky has already taken 25 pages of notes on her own and she will take 5 pages during each hour of class. in all how many hours

will vicky have to spend in class before she will have a total of 40 pages of notes in her notebook?

1 answer:

Lilit [14]3 years ago

5 0

The answer 24..................

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An average soccer player travels 7 miles during a game. A typical field is 104 meters long. How many times did the average socce

marissa [1.9K]

Answer:

About 108 times

Step-by-step explanation:

Given:

An average soccer player travels 7 miles during a game

A typical field is 104 meters long.

To find:

How many times did the average soccer play travel the length of the field?

Solution:

An average soccer player travels during the game = 7 miles

First convert 7 miles into meters, 1 mile = 1609.34 meter

7 mile = 1609.34 \times 7 = 11265.41 m

Length of field = 104 meters

To find number of times average soccer player travel the length of the field, we will divide an average soccer player travels during the game by Length of field

11265.41 m $\div$ 104 = 108.32

Therefore, about 108 times average soccer player travel the length of the field

8 0

3 years ago

Find the value of y

bulgar [2K]

Answer:

$m\angle y=48^o$

Step-by-step explanation:

we know that

The inscribed angle is half that of the arc comprising

so

$m\angle y=\frac{1}{2}[96^o]$

$m\angle y=48^o$

6 0

2 years ago

Y = 2(x – 4)– 6<br> Vertex:<br> y-intercept: _

serious [3.7K]

Answer:

vertex: (4,-6), y= -14

Step-by-step explanation:

vertex can be derived from this formula

(4, -6)

to find y intercept you need to set x=0

y=2(0-4)-6

=-8-6

y= -14

4 0

3 years ago

a fruit delivers its fruit in two types of boxes: large and small. a delivery of 3 large boxes and 5 small boxes has a total wei

Masteriza [31]

Answer:

The weight of a small box = 13.5 kg

The weight of 1 large box = 18.5 kg

Step-by-step explanation:

Let us assume the weight of a small box = m kg

And the weight of 1 large box = n kg

Now, the weight of 5 small box = 5 x (weight of 1 small box) = 5 m

Also, the weight of 3 large box = 3 x (weight of 1 large box) = 3 n

Here, 3 large boxes + 5 small boxes = of 123 kilograms

⇒ 5 m + 3 n = 123 .... (1)

Again, the weight of 2 small box = 2 x (weight of 1 small box) = 2 m

Also, the weight of 12 large box = 12 x (weight of 1 large box) = 12 n

Here, 12 large boxes + 2 small boxes = 249 kilograms

⇒ 2 m+ 12 n = 249 .... (2)

Now, solving both the given equations by ELIMINATION, we get:

5 m + 3 n = 123 x (2)

2 m+ 12 n = 249 x (-5)

we get the new set of equitation as:

10 m + 6 n = 246

- 10 m - 60 n = -1245

Adding both equation, we get

-54 n = 999

or, n = 18.5

Now, 5 m + 3 n = 123

So, 5 m = 123 -3 (18.5) = 123 - 55.5 = 67.5

⇒ m = 13.5

Hence, the weight of a small box = m kg = 13.5 kg

And the weight of 1 large box = n kg = 18.5 kg

8 0

3 years ago

(3 − 4i)(5 + 2i)<br><br> A. 15 − 8i<br> B. 23 − 14i<br> C. 15 − 8i2<br> D. 15 − 14i − 8i2

choli [55]

Answer:

B.23-14i

Step-by-step explanation:

(3x5)+(3x2i)-(4ix5)-(4ix2i)

15+6i-20i-8(-1)

15+6i-20i+8

23-14iฟ

8 0

3 years ago