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2 years ago

I'm confused on this can you guys please help me. <:

Mathematics

2 answers:

V125BC [204]2 years ago

8 0

Answer:

D. h

Step-by-step explanation:

Since the unknown is height, and height starts with the letter h, h would be most meaningful.

Answer: D. h

Margaret [11]2 years ago

7 0

Answer:

Step-by-step explanation:

because you would have to say x which is the height of the flagpole minus 3

x-3

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HELP PLS! asap!! what is the resulting ordered pair if the value of the independent variable is 5?

Serga [27]

Independent variable is 5 means x = 5
solve for f(x) when x = 5
f(5) = -2(5) +1
f(5) = -10 + 1
f(5) = -9

Solution (5,-9)

Answer
B. (5,-9)

6 0

3 years ago

Read 2 more answers

I need graph help plz

Likurg_2 [28]

Answer:

Step-by-step explanation:

Part A

x-intercepts of the graph → x = 0, 6

Maximum value of the graph → f(x) = 120

Part B

Increasing in the interval → 0 ≤ x ≤ 3

Decreasing in the interval → 3 < x ≤ 6

As the price of goods increase in the interval [0, 3], profit increases.

But in the price interval of (3, 6] profit of the company decreases.

Part C

Average rate of change of a function 'f' in the interval of x = a and x = b is given by,

Average rate of change = $\frac{f(b)-f(a)}{b-a}$

Therefore, average rate of change of the function in the interval x = 1 and x = 3 will be,

Average rate of change = $\frac{f(3)-f(1)}{3-1}$

= $\frac{120-60}{3-1}$

= 30

6 0

2 years ago

10 less the quotient of a number and 3 is 6

Lelu [443]

This means subtract something from the number <span>10</span>

5 0

3 years ago

Read 2 more answers

PLEASE HELO ASAP WILL MARK BRAINLIEST

ss7ja [257]

A.) 1/2

B.) 3

For the first one, just plug the value of x (4) everywhere you see x in the formula.

For the second one, place 1 wherever you see f(x)

Hope this helps

6 0

3 years ago

Suppose that a cyclist began a 476

mojhsa [17]

Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus $\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{eastbound cyclist}&d&r&8.5\\
\textit{westbound car}&476-d&r+33.2&8.5
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
\boxed{d}=8.5r\\\\
476-d=(r+33.2)8.5\\
----------\\
476-\boxed{8.5r}=(r+33.2)8.5
\end{cases}$

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2

6 0

3 years ago