Sandy ran 5 ½ during the second hour.
- Total amount Sandy used to jog for 2 hours = 13 miles
- Amount Sandy used to run in the 1st hour = 7 ½
<h2>Further Explanation</h2>
Therefore the amount Sandy used to run in the 2nd hour = Total amount Sandy used to jog for 2 hours – Amount Sandy used to run in the 1st hour
= 13 – 7 ½ (and can be expressed as 7 + ½)
= 13 – (7 + ½)
= 13 – 7 – ½
= 6 – ½ (otherwise expressed as 6/1 – 1/2)
= (6 x 2) – (1 x 1) / 2
= (12) – (1) / 2
= 12 – 1 / 2
= 11/2
= 5 ½
Hence, Sandy ran 5 ½ miles during the second hour.
Based on the above expression, it is observed that there is an element of fractions in the math problem. Also, BODMAS was clearly used to derive the solution to the given question.
Recall, 13 – (7 + ½). The mathematical signs, (–) and (+) were multiplied; one of mathematics rule states that – x + = –; thus 13 – 7 – ½
Notably, fractions deal with denominators and numerators; and in these questions, with the help of BODMAS, they (6/1 – 1/2) were used to factor each other out to derive the final answer 5 ½.
LEARN MORE:
KEYWORDS:
- bodmas
- fractions
- mathematical sign
- denominators
- numerators
Answer:
<h2>
y = 5.6</h2>
Step-by-step explanation:
From Thales' theorem:
Answer:
Okay. I got:
FGCE
Step-by-step explanation:
Answer:
clockwise from left, the missing side lengths are 8 m, 13 m, 8 m
Step-by-step explanation:
The perimeter of the figure is the sum of the lengths of its sides. Sides with the same hash mark have the same length, so the perimeter (in meters) is ...
38 = (3x+1) +(2x) +(9) +(2x)
38 = 7x +10
28 = 7x . . . . . . subtract 10
4 = x . . . . . . . . divide by 7
Then the short sides are ...
2x = 2·4 = 8 . . . meters
and the long side is ...
3x+1 = 3·4 +1 = 13 . . . meters
Answer:
21
Explanation:
To solve this problem, you substitute in the 5 for the x creating this equation: f(5)=6+3(5).
f(5)=15+6
f(5)=21
