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SashulF [63]
3 years ago
6

Can you help me with this physics homework? please

Physics
1 answer:
KengaRu [80]3 years ago
3 0

Answer:

Area under a curve can be estimated via block counting, calculated with simple geometry if the velocity has constant accelerations, or calculated by integration if the velocity can be described by a mathematical equations.

The area under a velocity time curve will be the product of velocity and time which equals displacement.

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Harry and Sally are sitting on opposite sides of a circus tent when an elephant trumpets a loud blast. If Harry experiences a so
FromTheMoon [43]

To solve this problem we will start from the definition of the decibels which refers to the log relationship of the intensities, mathematically each decibel of the people can be described as follows

dB_1 = 10log(\frac{I_1}{I_o})

dB_2 = 10log(\frac{I_2}{I_o})

dB_1 - dB_2 = 10log(\frac{I_1}{I_2})

\frac{67-45}{10} = log(\frac{I_1}{I_2})

log(\frac{I_1}{I_2}) = \frac{11}{5}

For properties of the logarithm then we have that,

\frac{I_1}{I_2} = 10^{11/5}

\frac{I_1}{I_2} = 158.48

We have the relation

\frac{r_2^2}{r_1^2} = 158.48

\frac{r_2}{r_1} = \sqrt{158.48}

\frac{r_2}{r_1} = 12.58

7 0
3 years ago
What is the amplitude of photo as they passed a black hole​
aalyn [17]

Answer:

Explanation:

It is you moma

7 0
3 years ago
To practice problem-solving strategy 9.1 a strategy for conservation of momentum problems. an 80-kg quarterback jumps straight u
kherson [118]
Refer to the diagram shown below.

By definition momentum =  mass *  velocity.

Before throwing the ball:
The initial momentum is
P₁ = 0.

After throwing the ball:
Let u = the backward velocity of the quarterback.
The momentum is 
P₂ = (0.43 kg)*(15 m/s) + (80 kg)*(- u m/s)

Conservation of momentum requires that
P₂ = P₁
6.45 - 80u = 0
u = 6.45/80 = 0.0806 m/s

Answer: 0.08 m/s backward

6 0
3 years ago
Read 2 more answers
A 4-79 permalloy solenoid coil needs to produce a minimum inductance of 1.1 . If the maximum allowed current is 4 , how many tur
daser333 [38]

The related concept to solve this exercise is given in the expressions that the magnetic field has both as a function of the number of loops, current and length, as well as inductance and permeability. The first expression could be given as,

The magnetic field H is given as,

H = \frac{nI}{l}

Here,

n = Number of turns of the coil

I = Current that flows in the coil

l = Length of the coil

From the above equation, the number of turns of the coil is,

n = \frac{Hl}{I}

The magnetic field is again given by,

H = \frac{B}{\mu_t}

Where the minimum inductance produced by the solenoid coil is B.

We have to obtain n, that

n = \dfrac{\frac{B}{\mu_t}l}{I}

Replacing with our values we have that,

n = \dfrac{\frac{1.1Wb/m^2 }{200000}(2m)}{4mA}

n = \dfrac{(\frac{1.1Wb/m^2 }{200000})(\frac{10^4 guass}{1Wb/m^2})(2m)}{4mA(\frac{10^{-3}A}{1mA})}

n = 27.5 \approx 28

Therefore the number of turn required is 28Truns

4 0
4 years ago
If it took 125 seconds to complete 5 wave cycles, what is the period of the wave?
finlep [7]

The period of the wave is 25 s

<u>Explanation:</u>

To find the period of the wave, we have the formula

T= seconds/ no of cycle

T= 125/5

T= 25 s

The period of the wave is 25 s

4 0
4 years ago
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