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3 years ago

What effects can occur when heat energy is added to a system?

1 answer:

6 0

I think there would be three answers from the choices. The effects that can occur when heat energy is added to a system would be that increase in temperature, change of state and phase change Hope this answers the questions. Have a nice day.

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A triangular plate with base 4 m and height 5 m is submerged vertically in water so that the tip is even with the surface. Expre

Artyom0805 [142]

Answer:

hydrostatic force is 327000.00 N

Explanation:

given data

base = 4 m

height = 5 m

density of water = 1000 kg/m3

to find out

hydrostatic force

solution

we know this is a triangle so we consider here a small strip PQ whoes area da in with length x and width dy

so area will be

da = base/H × height = base/H × y

so da = x dy = base/H × y dy

and we know pressure = ρ × g × h

here h = y

hydrostatic force = pressure × area

df = (ρ × g × h) × base/H × y dy

now integrate it from 0 to 5 height

f = ρ × g $\int_{0}^{5} (h) (base/H)ydy$

f = ρ × g $\int_{0}^{5} (y) (4/5)ydy$

f = ρ × g × 4/5 × $(y^{3} /3)^{5} _0$

now put value ρ = 1000 and g = 9.81

f = ρ × g × 4/5 × $(y^{3} /3)^{5} _0$

f = 1000 × 9.81 × 4/5 × (5³/3)

force = 7848 × 41.666667

force = 327000.00 N

hydrostatic force is 327000.00 N

4 0

2 years ago

Read 2 more answers

E electric- and magnetic-field what is the direction of propagation of the wave?

castortr0y [4]

As well as the electric and magnetic fields being perpendicular to eachother, a wave moves perpendicularly to both

8 0

3 years ago

State a situation in which force is applied on a body, but no work is done

LenaWriter [7]

If you press on your arm force is applied work done is if it moves.
One answer could be if I was to press my hand on a table.
Have a great day!

8 0

2 years ago

Read 2 more answers

2. Kevin works as a janitor, and he is pushing a fully-

dybincka [34]

The time taken for him to move the bin 6.5 m is 2.30 s.

The given parameters;

weight of the load, w = 557 N
force applied , F = 410 N
angle of force, = 15°
coefficient of kinetic friction = 0.46
distance moved, d = 6.5 m

The net horizontal force on the recycling bin is calculated as follows;

$Fcos\theta - F_k = ma$

where;

m is the mass of the recycling bin
$F_k$ is the frictional force

W = mg

$557 = 9.8m\\\\m = \frac{557}{9.8} \\\\m = 56.84 \ kg$

The net horizontal force on the recycling bin is calculated as;

$Fcos \theta - F_k = ma\\\\Fcos\theta - \mu_kF_n = ma\\\\410\times cos(15) \ - \ 0.46(557) = 56.84 a\\\\139.8 = 56.84a\\\\a = \frac{139.8}{56.84} \\\\a = 2.46 \ m/s^2$

The time taken for him to move the bin 6.5 m is calculated as follows;

$s = v_0t + \frac{1}{2} at^2\\\\6.5 = 0 + \frac{1}{2} \times 2.46\times t^2\\\\6.5 = 1.23 t^2\\\\t^2 = \frac{6.5 }{1.23} \\\\t^2 = 5.285\\\\t = \sqrt{5.285} \\\\t = 2.30 \ s$