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nydimaria [60]
2 years ago
12

Un tubo cilindrico hueco de cobre mide 3 m de longitud tienen un diametro exterior de 4cm y un diametro interior de 2 cm¿cuanto

pesa?
Physics
1 answer:
Irina-Kira [14]2 years ago
4 0

Answer:

 W = 9.93 10² N

Explanation:

To solve this exercise we must use the concept of density

           ρ = m / V

the tabulated density of copper is rho = 8966 kg / m³

let's find the volume of the cylindrical tube

           V = A L

           V = π (R_ext  ² - R_int ²) L

let's calculate

          V = π (4² - 2²) 10⁻⁴  3

          V = 1.13 10⁻²  m³

         m = ρ V

        m = 8966 1.13 10⁻²

        m = 1.01 10² kg

the weight of the tube

        W = mg

         W = 1.01 10² 9.8

         W = 9.93 10² N

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Which cells or organs are considered to be part of both the immune and lymphatic systems? Select all that apply.
Leviafan [203]

Answer:

lymph nodes

tonsils and adenoids

thymus

Explanation:

-Arteries are the blood vessels that take the blood that contains oxygen from the heart to the tissues and are part of the circulatory system.

-Lymph nodes are glands that take care of filtering the fluid that goes through the lympathic system and are also important for the functioning of the immune system.

-Capillaries are blood vessels that connect the veins and arteries and are part of the circulatory system.

-Tonsils and adenoids are located in the throat and they help protect the body from diseases and they are part of immune system and the lympathic system.

-Veins are the vessels that take the blood to the heart and they are part of the circulatory system.

-Thymus is an organ in which the T cells develop and they help protect the body against virus and bacteria and it is part of the immune and lympathic systems.

According to this, cells or organs that are considered to be part of both the immune and lymphatic systems are:

lymph nodes

tonsils and adenoids

thymus

8 0
3 years ago
Which of the following is true?
lesantik [10]

Answer:

D

Explanation:

What it means to be an autotroph is that you make your own food and plants do that by photosynthesis to be a heterotroph is finding food from other sources like autotrophs or even other heterotrophs

3 0
3 years ago
Read 2 more answers
If the frequency of the incoming light is increased, will the energy of the ejected electrons increase, decrease, or stay the sa
Arlecino [84]

Answer:

increase

Explanation:

According to Einstein's photoelectric equation; the energy of a photon striking a metal surface is related to the kinetic energy of the ejected photoelectron by the formula;

KE= hf - hfo

Where h is the planks constant, f and fo refer to the frequency of incident photon and the threshold frequency respectively.

Hence, we can clearly see from the foregoing that the kinetic energy of the ejected photoelectron is proportional to the frequency of the incident photon.

Hence, if the frequency of the incident photon is increased, the kinetic energy of the ejected photoelectron increases also.

3 0
3 years ago
What is temperature? <br>how temperature can be measured​
german

Answer:

Temperature is the kinetic energy of the particles of a substance.

Explanation:

The more kinetic energy a particle has the higher it's temperature. In the case of the atmosphere, which is what we are primarily concerned with in Meteorology, we measure this using a mercury thermometer (in certain situations we use an alcohol thermometer and of course modern times have given us things like dewcells and digital thermometers but we always go back to the mercury thermometer for accuracy).

3 0
1 year ago
What frequency (in Hz) is received by a person watching an oncoming ambulance moving at 116 km/h and emitting a steady 950 Hz so
Arte-miy333 [17]

To solve this problem we will apply the concepts related to the Doppler Effect, defined as the change in apparent frequency of a wave produced by the relative movement of the source with respect to its observer. Mathematically it can be written as

f_{obs} = f(\frac{v_w}{v_w-v_s})

Here,

f_s= Frequency of the source

v_w = Speed of the sound

v_s= Speed of source

Now the velocity we have that

v_s = 116km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

v_s = 32.22m/s

Then replacing our values,

f_{obs} = (950Hz) (\frac{345m/s}{345m/s-32.22m/s})

f_{obs} = 1047.86Hz

Therefore the frequency of the observer is 1047.86Hz

8 0
3 years ago
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