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Nostrana [21]
3 years ago
12

4. A while ago, the price of a certain candy was 9 US cents per ounce in the U.S.,

Mathematics
1 answer:
Sati [7]3 years ago
7 0
9 (cents per ounce) multipled by 16 (amount of ounces to make a pound) which makes 1 pound of candy 1.44 USD. Using the information given, 1.2 CAN dollars is equal to 0.96 dollars. Making the Canadian candy more cheaper.
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Solve for s.<br> 0.5s +1= 7+ 4.58<br> S =?
Lana71 [14]

Answer:

s = 21.16

Step-by-step explanation:

0.5s +1= 7+ 4.58

Combine like terms

0.5s +1=11.58

Subtract 1 from each side

0.5s +1-1= 11.58-1

.5s = 10.58

Multiply by 2

.5s *2 = 10.58*2

s = 21.16

4 0
3 years ago
Read 2 more answers
Which interval describes where the graph of the function is positive?
Ad libitum [116K]

Answer:

D is the correct answer.

Step-by-step explanation:

Find the portion of the graph that is above the x-axis.

8 0
2 years ago
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How to find a
Olegator [25]
In reality your common denominator should be the Least Common Multiple. The LCM is the product of highest occurring primes of the numbers prime factorizations...

4=2*2, and 12=2*2*3.  So the LCM is 2*2*3=12  Now that you know what the least common multiple is we can say that:

(3/4)(3/3)+5/12

9/12+5/12

(9+5)/12

14/12

7/6  which should be converted to a mixed number as this is an improper fraction...

(6+1)/6

1+1/6

1 1/6
4 0
4 years ago
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Wrong question???????
melomori [17]

Answer:

what do you mean ???????????

4 0
3 years ago
The teachers of the two classes want to compare the heights of their students. Which statements about the data sets are accurate
aleksandr82 [10.1K]

This question is incomplete.

Complete question

The sets of data below show the heights, in inches, of students in two different preschool classes.

A) a box plot titled class 1.

The number line goes from 38 to 49. the whiskers range from 39 to 48, and the box ranges from 40 to 43. a line divides the box at 41.

class 1

B) A box plot titled class 2.

The number line goes from 38 to 49. the whiskers range from 38 to 49, and the box ranges from 39 to 42. a line divides the box at 41.

class 2

The teachers of the two classes want to compare the heights of their students. Which statements about the data sets are accurate? Select three options.

• Because the sets are symmetrical, the mean should be used to compare the data sets.

• Because the sets do not contain outliers, the MAD should be used to compare the data sets.

•Because the sets are not symmetrical, the IQR should be used to compare the data sets.

•Because the sets contain outliers, the median should be used to compare the data sets.

•The mean and mode cannot be accurately determined based on the type of data display.

Answer:

• Because the sets are not symmetrical, the IQR should be used to compare the data sets.

• Because the sets contain outliers, the median should be used to compare the data sets.

• The mean and mode cannot be accurately determined based on the type of data display.

Step-by-step explanation:

In the above question, we can see that a teacher intends to compare the heights of students from two different classes.

Because the data sets to be obtained would contain heights from different classes the results obtained would be non symmetrical.

Hence the best statistical analysis to use to solve for or to compare a set of non symmetrical data is known as either the Median or an Interquartile range.

It is important to note that a non symmetrical data would most likely contain or include the presence of outliers.

8 0
3 years ago
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