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zheka24 [161]
3 years ago
12

3 3/8 divided by 2 1/4 ILL GIVE BRAINLEIST

Mathematics
2 answers:
Nezavi [6.7K]3 years ago
7 0

Answer:

I missed the part where that's my problem

kobusy [5.1K]3 years ago
3 0

Answer:

1 1/2

Step-by-step explanation:

Divide

3 and 3 over 83

3

8

÷ 2 and 1 over 42

1

4

= 108 over 72

108

72

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WILL GIVE BRAINLIEST IF RIGHT
fenix001 [56]
Im not sure but i think it is 1.6 and why is because if you divide 9.6 cm with 6 cm it equals up to 1.6 cm
3 0
3 years ago
5 + 2x/ 3x - 1 = 6/7
expeople1 [14]

Step-by-step explanation:

5-1+0.85= -0.666x

4.85/-0.666= -0.666/-0.666x

x= -5.6

6 0
3 years ago
after 1 second the rock is 129 feet in the air; after 2 seconds, it is 236 feet in the air. find the height, in feet of the rock
harina [27]

Answer:

557 feet

Step-by-step explanation:

1s --> 129

2s --> 236

1 to 2 is 107 feet

107*4=428

129 --> 1

129+107*4

129+428

557

3 0
3 years ago
a team's stadium has a capacity of 86,047. The fan base is notorious for selling out of tickets every game. If every game sells
ycow [4]

Answer:

1,032,564 tickets

Step-by-step explanation:

Find how many tickets they sell in total by multiplying the capacity of the stadium by the number of games in the season:

86,047(12)

= 1,032,564

So, if every game sells out, 1,032,564 tickets will be sold.

5 0
3 years ago
Suppose a couple planned to have three children. Let X be the number of girls the couple has.
sesenic [268]

Answer:

a) {GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) {0,1,2,3}

c)

P(X=2) = \dfrac{3}{8}

d)

P(\text{3 boys}) = \dfrac{1}{8}

Step-by-step explanation:

We are given the following in the question:

Suppose a couple planned to have three children. Let X be the number of girls the couple has.

a) possible arrangements of girls and boys

Sample space:

{GGG, GGB, GBG, BGG, BBG, BGB, GBB, BBB}

b) sample space for X

X is the number of girls couple has. Thus, X can take the values 0, 1, 2 and 3 that is 0 girls, 1 girl, 2 girls and three girls from three children.

Sample space: {0,1,2,3}

c) probability that X=2

P(X=2)

That is we have to compute the probability that couple has exactly two girls.

\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}

Favorable outcome: {GGB, GBG, BGG}

P(X=2) =\dfrac{3}{8}

d) probability that the couple have three boys.

Favorable outcome: {BBB}

P(BBB) = \dfrac{1}{8}

8 0
3 years ago
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