Question

Calculate the approximate volume of a 0.600 mol sample of gas at 15.0°c and a pressure of 1.10 atm.

Answer 1

Answer:

$0.013 m^3$

Explanation:

The problem can be solved by using the ideal gas equation:

$pV=nRT$

where

$p=1.10 atm = 1.11\cdot 10^5 Pa$ is the gas pressure

$V$ is the gas volume

n = 0.600 is the number of moles of the gas

$R=8.314 J/(mol K)$ is the gas constant

$T=15.0^{\circ}+273.15=288.15 K$ is the absolute temperature of the gas

Solving the equation for V, we find the volume of the gas:

$V=\frac{nRT}{p}=\frac{(0.600 mol)(8.314 J/(mol K))(288.15 K)}{1.11\cdot 10^5 Pa}=0.013 m^3$