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Viefleur [7K]
2 years ago
5

A motor does a total of 480 J of work if 5 s to lift a 12 clock to the top of a ramp. The average power developed by the motor i

s
Physics
2 answers:
yawa3891 [41]2 years ago
7 0

Answer:

ok,lets go.

Explanation:

Average power =work/time

P=480j/5s

P=96W

marta [7]2 years ago
3 0

Answer:

Power = work / time

P = 480 / 5 = 96W

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A bowling ball weighing 71.7 N is attached to the ceiling by a rope of length 3.73 m . The ball is pulled to one side and releas
vekshin1

Answer:

A) a = 5.673 m/s²

The direction will be upwards vertically towards the point where it is suspended.

B) T = 113.2 N

Explanation:

A) We are given;

Weight of bowling ball; W = 71.7 N

Speed; v = 4.6 m/s

Rope length; r = 3.73 m

Now, formula for the centripetal acceleration is;

a = v²/r

Thus; a = 4.6²/3.73

a = 5.673 m/s²

The direction will be upwards vertically towards the point where it is suspended.

B) since weight is 71.7 N, it means that;

Mass = weight/acceleration = 71.7/9.8

Mass(m) = 7.316 kg

Thus,

Centripetal force is;

F_cent = 7.316 × 5.673

F_cent = 41.5 N

Thus, Tension in the rope is;

T = W + F_cent

T = 71.7 + 41.5

T = 113.2 N

4 0
3 years ago
The answer using the graphical method and analytical method of vector addition will always be.
Alex17521 [72]

The answer using the graphical method and analytical method of vector addition will always be

C. Same

Analytic method means adding vectors (x₁,y₁) and (x₂,y₂) give (x₁+x₂,y₁+y₂)

Example: Addition of (2,3) and (1,1) gives (3,4)

Solving it graphically will also give (3,4)

4 0
3 years ago
The part of Earth's rocky outer layer that makes up the land masses is the
tangare [24]
D

Giddy UP!!!!!!!!!!!!!!!!!!!!!
4 0
3 years ago
Because of interstellar dust, astronomers can see at most about 5 kpc into the disk of the galaxy at visual wavelengths. What pe
NNADVOKAT [17]

Answer:

96%

Explanation

Let A the total area of the galaxy, is modeled as a disc:

A = πR^2 = π (25 kpc)^2

And let a be the area that astronomers are able to see:

a = πr^2 = π(5 kpc)^2

The percentage that can be seen is equal to 100 times the ratio of the areas, of the galaxy and the "visible" part:

P = 100 a/A = (5/25)^2 = 100/25 = 4%

Therefore, the percentage of the galaxy not included, i.e. not seen is:

(100-4)% = 96%

5 0
3 years ago
A series circuit is composed of two resistors:
WITCHER [35]
<h3>Answer:</h3>

1.3 Amps

<h3>Explanation:</h3>

<u>We are given;</u>

A circuit with resistors, R1 and R2

R1 = 7 Ω

R2 = 11 Ω

Voltage = 24 V

We are required to calculate the current in the circuit.

<h3>Step 1: We need to find the effective resistance.</h3>

When resistors are arranged in series, the effective resistance is calculated by;

Rt = R₁ + R₂ + R₃ + ..........Rₙ

Therefore;

Total resistance = 7 + 11

                          = 18 Ω

<h3>Step 2: Calculate the current in the circuit</h3>

From the ohm's law;

V = IR

Rearranging the formula;

I = V/R

Thus;

I = 24 V ÷ 18 Ω

 = 1.333 Amps

= 1.3 Amps

Thus, the current in the circuit is 1.3 Amps

7 0
3 years ago
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