Answer:
The magnitude of the acceleration of the box is 2 m/s².
Explanation:
Given:
Mass of the box, 
kg
Force acting towards east, 
N
Frictional force acting towards west, 
N
Let the acceleration be 
m/s².
Now, net force acting on the box towards east is given as:
From Newton's second law of motion,
Therefore, the magnitude of the acceleration of the box is 2 m/s².
Answer:
1.68N
Explanation:
W=F*d
KE=1/2*M*V^2
M=32kg
V= 5.1m/s
D=50m
0.5(32)(5.1^2)= 416 J
Initial energy=500 J
final energy= 416 J
lost energy= 500-416
heat lost to friction=84 J
84=F*50
84/50=F*50/50
F=1.68N
Answer:
the ratio of distance travelled by effort to the distance travelled by load in the machine is called velocity ratio (VR)
Energy released during an earthquake travels in the form of waves<span> around the Earth. Two types of seismic </span>wave<span> exist, </span>P<span>- and </span>S-waves<span>. They are different in the way that they travel through the Earth. ... They are transverse </span>waves<span> which mean the </span>vibrations<span> are at right angles to the direction of travel.</span>
The phase is called 3rd quarter.
Hope this helps:)
