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Sonja [21]
4 years ago
6

Which is an example of a situation where a zero is not considered to be a

Chemistry
1 answer:
ludmilkaskok [199]4 years ago
7 0

Answer:

B. When it is obtained by rounding, as in 3.0

Explanation:

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when aqueous solutions of table salt and silver nitrate are mixed a white solid forms. this solid is____?
elena55 [62]
When aqueous solutions of table salt and silver nitrate are mixed a white solid forms. This solid is called a precipitate. <span>A </span>precipitate<span> is an insoluble solid that emerges from a liquid solution. </span>The process of forming this solid is called precipitation. 
5 0
4 years ago
The equilibrium constant, Kp, for the following reaction is 9.52×10-2 at 350 K: CH4(g) + CCl4(g) 2CH2Cl2(g) Calculate the equili
dimaraw [331]

Answer:

pCH4 =  0.9184 atm

pCCl4 = 0.9184 atm

pCH2Cl2 = 0.2832 atm

Explanation:

Step 1: Data given

The equilibrium constant, Kp= 9.52 * 10^-2

Temperature = 350 K

Each have an initial pressure of 1.06 atm

Step 2: The balanced equation

CH4(g) + CCl4(g) ⇆ 2CH2Cl2(g)

Step 3: The pressure at the equilibrium

pCH4 = 1.06 - X atm

pCCl4 = 1.06 - X atm

pCH2Cl2 = 2X

Step 4: Calculate Kp

Kp = (2X)² / (1.06 - X)*(1.06 - X)

9.52 * 10^-2 = 4X² / (1.06 - X)*(1.06 - X)

X = 0.1416

Step 5: Calculate the partial pressure

pCH4 = 1.06 - 0.1416 =  0.9184 atm

pCCl4 = 1.06 - 0.1416 =  0.9184 atm

pCH2Cl2 = 2 * 0.1416 = 0.2832 atm

Kp = (0.2832²) / (0.9184*0.9184)

Kp = 9.52 * 10^-2

pCH4 =  0.9184 atm

pCCl4 = 0.9184 atm

pCH2Cl2 = 0.2832 atm

3 0
3 years ago
Ammonium hydrogen sulfide (NH4HS) can
Sergeu [11.5K]

K_c = \frac{[NH_2]^{1}[H_2S]^{1}}{[NH_2HS]^{1}} is the equilibrium constant expression for

NH₂HS(S)   →   NH₂(g) + H₂S(g). Hence, option A is correct.

<h3>Definition of equilibrium constant.</h3>

A number that expresses the relationship between the amounts of products and reactants present at equilibrium in a reversible chemical reaction at a given temperature.

Equilibrium constant for the NH₂HS(S)   →   NH₂(g) + H₂S(g) will be:

K_c = \frac{[Product]^{coefficient}}{[Reactantt]^{coefficient}}

K_c = \frac{[NH_2]^{1}[H_2S]^{1}}{[NH_2HS]^{1}}

Hence, option A is correct.

Learn more about the equilibrium constant here:

brainly.com/question/10038290

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8 0
3 years ago
How does the final paragraph relate to the main idea of the article? (4.03) science.
V125BC [204]

Answer:

Indicates the writer's stance on the main idea of a paragraph. The controlling idea appears in the paragraph's topic sentence. ... The final sentence of a paragraph that summarizes the topic sentence using different words. Words and phrases that show how the ideas in sentences and paragraphs are related.

Explanation:

HOPE THIS HELP

PICK ME AS THE BRAINLIEST

5 0
3 years ago
Carbon disulfide, CS2, can be made from coke, C(s), and sulfur dioxide, SO2(g). C(s) + SO2(g) à CS2(s) + CO2(g) If the actual yi
Virty [35]

Answer:

450g of coke (C)

Explanation:

Step 1:

The balanced equation for the reaction is given below:

3C(s) + 2SO2(g) —> CS2(s) + 2CO2(g)

Step 2:

Determination of the mass of C that reacted and the mass of CS2 produced from the balanced equation.

This is illustrated below:

Molar Mass of C = 12g/mol

Mass of C from the balanced equation = 3 x 12 = 36g

Molar Mass of CS2 = 12 + (32x2) = 12 + 64 = 76g/mol.

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Step 3:

Determination of the mass of C required to produce 950g of CS2. This is illustrated below:

From the balanced equation above, 36g of C reacted to produce 76g of CS2.

Therefore, Xg of C will react to produce 950g of CS2 i.e

Xg of C = (36 x 950)/76

Xg of C = 450g

From the calculations made above, 450g of coke (C) is needed to produce 950g of CS2.

6 0
3 years ago
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