The zeros of a quadratic equation are equal to the x-intercepts of its graph. In other words, you must find the x-value that causes the expression to equal zero. Start by adding 4 to both sides of the equation:
X² - 5x + 4 = 0
Factor the equation:
(x - 1)(x - 4) = 0
Now calculate each piece separately, starting with the first one:
x - 1 = 0
Add 1 to both sides of the equation:
x = 1
We have proven that x = 1. Now calculate the second piece:
x - 4 = 0
Add 4 to both sides of the equation:
x = 4
We have proven that x = 4. Consequently, we have proven that (x = 1) and (x = 4) are the two zeros of this quadratic equation.
I hope this helps!
Evaluate 2(x + 1) - 3 when x = 6.
First, plug in x value.
2(6 + 1) -3 ParenthesisEMDAS
2(7) - 3 PEMultiplyDAS
14 - 3 PEMDASubtract
11 ←
18/25, 51/75, 33/50, 13/20, 3/5
25 - 21 = 4 questions of his history incorrectly ;
4 / 25 = 0.16 represents the fraction of problems he answered incorrectly ;
Answer
f(6) = -33 and g(-3) = -52
Explanation;
Given the function
f(x)=-5x-3
f(6)=-5(6)-3
f(6) = -30 -3
f(6) = -33
Similarly if g(x)=2x^3+2
g(-3)=2(-3)^3+2
g(-3) = 2(-27)+ 2
g(-3) = -54 + 2
g(-3) = -52
Hence f(6) = -33 and g(-3) = -52
