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Harlamova29_29 [7]

2 years ago

6

Use the formula D= RT to solve the problem. Mrs. Warren traveled 1,069 miles from Vian, OK to Raleigh NC at an average rate of 6

5 mph. Approximately how many hours was she driving? Solve this equation. 1,069 = 65T
A. 14 hours
B. 16 hours
C. 18 hours
D. 20 hours

1 answer:

zalisa [80]2 years ago

5 0

The answer is C!!!!!!!!!!!!!!!!!!

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Wendy is creating a large soup based on a recipe. Her recipe calls for of a pint of milk, but she only has of a pint of milk, so

xeze [42]

Answer:

She can only make 5/6 of her recipe with the amount of milk that she has.

Step-by-step explanation:

Some data of this problem is missing, the data missing is:

Her recipe calls for 3/4 of a pint of milk and she only has 5/8 of a pint of milk.

Now, to know what's the portion she can do with that amount we need to divide the amount of milk she has by the total amount she needs:

$\frac{5}{8}$ ÷ $\frac{3}{4}$

When we divide we turn the second fraction upside down (the numerator becomes the denominator and viceversa) and multiply, thus:

$\frac{5}{8}$ ÷ $\frac{3}{4}=\frac{5}{8}$ × $\frac{4}{3} =\frac{20}{24}$

If we simplify this last expression we have:

$\frac{20}{24}=\frac{10}{12} =\frac{5}{6}$

Thus, she can only make 5/6 of her recipe with the amount of milk that she has.

<em>Note: In case the data missing is different, you can apply this same procedure with the fractions you have. </em>

6 0

3 years ago

Which of the following is a sequence that moves on a basis of addition and subtraction?

irinina [24]

It is the first answer

5 0

3 years ago

Use the mid-point rule with n = 4 to approximate the area of the region bounded by y = x3 and y = x. (10 points)

USPshnik [31]

See the graph attached.

The midpoint rule states that you can calculate the area under a curve by using the formula:
$M_{n} = \frac{b - a}{2} [ f(\frac{x_{0} + x_{1} }{2}) + f(\frac{x_{1} + x_{2} }{2}) + ... + f(\frac{x_{n-1} + x_{n} }{2})]$

In your case:
a = 0
b = 1
n = 4
x₀ = 0
x₁ = 1/4
x₂ = 1/2
x₃ = 3/4
x₄ = 1

Therefore, you'll have:
$M_{4} = \frac{1 - 0}{4} [ f(\frac{0 + \frac{1}{4} }{2}) + f(\frac{ \frac{1}{4} + \frac{1}{2} }{2}) + f(\frac{\frac{1}{2} + \frac{3}{4} }{2}) + f(\frac{\frac{3}{4} + 1} {2})]$
$M_{4} = \frac{1}{4} [ f(\frac{1}{8}) + f(\frac{3}{8}) + f(\frac{5}{8}) + f(\frac{7}{8})]$

Now, to evaluate your f(x), you need to look at the graph and notice that:
f(x) = x - x³

Therefore:
$M_{4} = \frac{1}{4} [(\frac{1}{8} - (\frac{1}{8})^{3}) + (\frac{3}{8} - (\frac{3}{8})^{3}) + (\frac{5}{8} - (\frac{5}{8})^{3}) + (\frac{7}{8} - (\frac{7}{8})^{3})]$

$M_{4} = \frac{1}{4} [(\frac{1}{8} - \frac{1}{512}) + (\frac{3}{8} - \frac{27}{512}) + (\frac{5}{8} - \frac{125}{512}) + (\frac{7}{8} - \frac{343}{512})]$

M₄ = 1/4 · (2 - 478/512)
= 0.2666

Hence, the <span>area of the region bounded by y = x³ and y = x</span> is approximately 0.267 square units.

6 0

3 years ago

The drawing shows Seth's plan for a fort in his backyard. Each unit square is 1 square foot.

barxatty [35]

Dyjfuncufgysfsrsycyfydtxyyfyd

7 0

3 years ago

Please help me with the worksheet

aivan3 [116]

Answer:

9) a = ¾, <u>vertex</u>: (-4, 2), <u>Equation</u>: y = ¾|x + 4| + 2

10) a = ¼, <u>vertex</u>: (0, -3), <u>Equation</u>: y = ¼|x - 0| - 3

11) a = -4, <u>vertex</u>: (3, 1), <u>Equation</u>: y = -4|x - 3| + 1

12) a = 1, <u>vertex</u>: (-2, -2), <u>Equation</u>: y = |x + 2| - 2

Step-by-step explanation:

<h3><u>Note:</u></h3>

I could <u><em>only</em></u> work on questions 9, 10, 11, 12 in accordance with Brainly's rules. Nevertheless, the techniques demonstrated in this post applies to all of the given problems in your worksheet.

<h2><u>Definitions:</u></h2>

The given set of graphs are examples of absolute value functions. The <u>general form</u> of absolute value functions is: y = a|x – h| + k, where:

|a| = determines the vertical stretch or compression factor (wideness or narrowness of the graph).

(h, k) = vertex of the function

x = h represents the axis of symmetry.

<h2><u>Solutions:</u></h2><h3>Question 9) ⇒ Vertex: (-4, 2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (0, 5) and substitute into the general form (equation):

y = a|x – h| + k

5 = a| 0 - (-4)| + 2

5 = a| 0 + 4 | + 2

5 = a|4| + 2

5 = 4a + 2

Subtract 2 from both sides:

5 - 2 = 4a + 2 - 2

3 = 4a

Divide both sides by 4 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{3}{4}\:=\:\frac{4a}{4}}$

a = ¾

Therefore, given the value of a = ¾, and the vertex, (-4, 2), then the equation of the absolute value function is:

<u>Equation</u>: y = ¾|x + 4| + 2

<h3>Question 10) ⇒ Vertex: (0, -3)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -2) and substitute into the general form (equation):

y = a|x – h| + k

-2 = a|4 - 0| -3

-2 = a|4| - 3

-2 = 4a - 3

Add 3 to both sides:

-2 + 3 = 4a - 3 + 3

1 = 4a

Divide both sides by 4 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{1}{4}\:=\:\frac{4a}{4}}$

a = ¼

Therefore, given the value of a = ¼, and the vertex, (0, -3), then the equation of the absolute value function is:

<u>Equation</u>: y = ¼|x - 0| - 3

<h3>Question 11) ⇒ Vertex: (3, 1)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -3) and substitute into the general form (equation):

y = a|x – h| + k

-3 = a|4 - 3| + 1

-3 = a|1| + 1

-3 = a + 1

Subtract 1 from both sides to isolate <em>a</em>:

-3 - 1 = a + 1 - 1

a = -4

Therefore, given the value of a = -4, and the vertex, (3, 1), then the equation of the absolute value function is:

<u>Equation</u>: y = -4|x - 3| + 1

<h3>Question 12) ⇒ Vertex: (-2, -2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (-4, 0) and substitute into the general form (equation):

y = a|x – h| + k

0 = a|-4 - (-2)| - 2

0 = a|-4 + 2| - 2

0 = a|-2| - 2

0 = 2a - 2

Add 2 to both sides:

0 + 2 = 2a - 2 + 2

2 = 2a

Divide both sides by 2 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{2}{2}\:=\:\frac{2a}{2}}$

a = 1

Therefore, given the value of a = -1, and the vertex, (-2, -2), then the equation of the absolute value function is:

<u>Equation</u>: y = |x + 2| - 2

5 0

2 years ago