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DIA [1.3K]
3 years ago
8

Make up your own multiplication and division problem and solve them

Mathematics
1 answer:
Marysya12 [62]3 years ago
7 0

Step-by-step explanation:

10.5 \div 5 = 2.1 \\

52.3 \times 2 = 104.6

82.5 \div 5 = 16.5

45 \times 6.5 = 292.5

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Triangles PQR and XYZ are similar.
laiz [17]

Answer:

Option A. 5.25 units

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

so

\frac{PR}{XZ}=\frac{QR}{YZ}

substitute the given values

\frac{7}{XZ}=\frac{4}{3}

solve for XZ

XZ=7(3)/4\\XZ=5.25\ units

7 0
3 years ago
Find the number of sides of a regular polygon if the sum of its interior angle is 1440
scoundrel [369]
The formula is 180(n-2)= 1140 then you divide 1140 by 180 to get 8 so then it would like like n-2=8 add the 2 over and n (being the number of sides)= 10 so your answer will be 10
8 0
3 years ago
0.02 percent of 5000 is what answer. please help im stuck
raketka [301]
0.02% of 5000 = 1 

 1 is the answer
8 0
3 years ago
Read 2 more answers
A chemist has 100 g of a 15% saline solution that she wants to strengthen to 29%. The percentage P of salt in the solution by ma
Vinil7 [7]

Answer:

D., x= 19.7 or ≈20. g

Step-by-step explanation:

P(x) = [100(15+x)]/(100+x)

When 0 g additional salt is added, x=0. we have

P(0) = [100(15+0)]/(100+0)= 15

x=0, P=15

We can see this point only on the graph D.

P(x) =29 = [100(15+x)]/(100+x)

29 = [100(15+x)]/(100+x)

29(100+x) = 100(15+x)

2900+29x = 1500+100x

2900-1500=100x-29x

1400 = 71x

x ≈ 19.7 g  or ≈20. g

From the graph D, we can see that to get 29% we need to add ≈ 20 g of salt.

4 0
3 years ago
In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample. To determine
zimovet [89]

Answer:

(a)  0.2650

(b)  0.0111

(c)  0.0105

(d)  0.0006

Step-by-step explanation:

Given that:

In microbiology, colony-forming units (CFUs) are used to measure the number of microorganisms present in a sample.

Suppose that the number of CFUs that appear after incubation follows a Poisson distribution with mean μ = 15.       &;

If the area of the agar plate is 75cm²;

what is the probability  of observing fewer than 4 CFUs in a 25 cm² area of the plate.

We can determine the mean number of CFUs that appear on a 25cm² area of the plate as follows;

75cm²/25cm² = 3

Since;

mean  μ = 15  

mean number of CFUs that appear on a 25cm² = 15/3 = 5 CFUs

Thus ; the probability of observing fewer than 4 CFUs in a 25 cm² area of the plate is estimated as:

= P(X < 4)

Using the EXCEL FUNCTION ( = poisson.dist(3, 5, TRUE) )

we have ;

P(X < 4) = 0.2650

b) If you were to count the total number of CFUs in 5 plates, what is the probability you would observe more than 95 CFUs?

Given that the total number of CFUs = 5 plates; then the mean number of CFUs in 5 plates =  15×5 = 75 CFUs

The probability is therefore = P( X > 95 )

= 1 - P(X ≤ 95)

= 1 - poisson.dist(95,75,TRUE) ( by using the excel function)

= 0.0111

c) Repeat the probability calculation in part (b) but now use the normal approximation.

Let assume that the mean and the variance of the poisson distribution are equal

Then;

X \sim N (\mu = 75 , \sigma^2 = 75)

We are to repeated the probability calculation in part (b) from above;

So:

P( X > 95 )

use the normal approximation

From standard normal variable table:

P(Z > 2.3094)

Using normal table

P(Z > 2.3094) = 0.0105

(d)  Find the difference between this value and your answer in part (b).

So;

the difference between the value in part c and part b is;

=  0.0111 - 0.0105

= 6*10^{-4}

= 0.0006 to four decimal places

5 0
4 years ago
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