3 years ago

What happens is a series circuit when you increase the number of bulbs?

1 answer:

Volgvan3 years ago

5 0

The bulbs will produce lesser light than their capacity, In short they will be dimmer because the the energy will get divided in the number of bulbs.

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A 720 kg roller-coaster starts off from Location A. Assuming friction does not impede the car's motion, what will be the change

vaieri [72.5K]

We know, Potential Energy = m * g * h
Here, mass & gravity would be same, but their height will change so it will be:

ΔU = U₂ - U₁
ΔU = mgh₂ - mgh₁
ΔU = mg (h₂ - h₁)

Hope this helps!

7 0

3 years ago

Read 2 more answers

If the amplitude of a simple harmonic oscillator is doubled, by what factor does the total energy increase?

dybincka [34]

Answer:

c)by a factor of four

Explanation:

The total energy of a simple harmonic oscillator is given by

$E=\frac{1}{2}kA^2$

where

k is the spring constant of the oscillator

A is the amplitude of the motion

In this problem, the amplitude of the oscillator is doubled, so

A' = 2A

Therefore, the new total energy is

$E'=\frac{1}{2}k(2A)^2=4(\frac{1}{2}kA^2)=4E$

So, the total energy increases by a factor 4.

6 0

3 years ago

a car's engine is only 12 % efficient at converting chemical energy in gasoline to mechanical energy. If it takes 18000 N of for

Georgia [21]

I wish i could help but idk the answer

6 0

3 years ago

A step-up transformer is connected to a generator that is delivering 141 V and 110 A. The ratio of the turns on the secondary to

hammer [34]

Answer:

31302 Volts and 55/111 Amps (≈0.5)

Explanation:

Secondary voltage / 141 = 1110 / 5

Secondary voltage = (1110*141) / 5

Secondary voltage = 31302

Amperage = 110/ (31302/141) = 55/111

5 0

4 years ago

A car with a constant velocity of 22 m/s is driven for 6.8 s. How far did it travel? (v =∆ d/∆t)

Genrish500 [490]

Answer:

C. 150 m

Explanation:

22 m/s x 6.8 = 149.6

3 0

4 years ago