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3 years ago

Question 1 Multiple Choice Worth 2 points)

Physics

1 answer:

Vinil7 [7]3 years ago

4 0

Answer:

2 atoms of oxygen in carbon dioxide

Explanation:

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What is the magnite of the net displacement of the mouse?

agasfer [191]

Complete Question

A field mouse trying to escape a hawk runs east for 5.0m, darts southeast for 3.0m, then drops 1.0m down a hole into its burrow. What is the magnitude of the net displacement of the mouse?

Answer:

The values is $s = 7.49 \ m$

Explanation:

From the question we are told that

The distance it travels eastward is $x = 5.0 \ m$

The distance it travel towards the southeast is $l = 3.0\ m$

The distance it travel towards the south is $z = 1 \ m$

Let x-axis be east

y-axis south

z-axis into the ground

The angle made between east and south is $\theta = 45^o$

The displacement toward x-axis is

$x = 5 + 3cos(45)$

$x = 7.12$

The displacement toward the y-axis is

$y = 3 * sin (45)$

$y = 2.123$

Now the overall displacement of the rat is mathematically evaluated as

$s = \sqrt{7.12^2 + 2.12^2 + 1^2}$

$s = 7.49 \ m$

3 0

3 years ago

krek1111 [17]

Explanation:

the table and the wooden block

6 0

3 years ago

Read 2 more answers

Complete the following

Furkat [3]

answer is down hera

3 0

2 years ago

A hunter aims at a deer which is 40 yards away. Her cross- bow is at a height of 5ft, and she aims for a spot on the deer 4ft ab

shutvik [7]

Answer:

a) θ₁ = 0.487º , b) t = 0.400 s , x = 11.73 ft

Explanation:

For this exercise let's use the projectile launch relationships.

The initial height is I = 5 ft and the final height y = 4 ft

y = y₀ + $v_{oy}$ t - ½ g t²

The distance to the band is x = 40 yard (3 ft / 1 yard) = 120 ft

x = v₀ₓ t

t = x / v₀ₓ

We replace

y –y₀ = v_{oy} x / v₀ₓ - ½ g x² / v₀ₓ²

v_{oy} = v₀ sin θ

v₀ₓ = vo cos θ

y –y₀ = x tan θ - ½ g x² / v₀² cos² θ

5-4 = 120 tan θ - ½ 32 120 / (300 2 cos2 θ)

1 = 120 tan θ - 0.0213 sec² θ

Let's use the trigonometry relationship

Sec² θ = 1 - tan² θ

1 = 120 tan θ - 0.0213 (1 –tan²θ)

0.0213 tan²θ + 120 tanθ -1.0213 = 0

We change variables

u = tan θ

u² + 5633.8 u - 48.03 = 0

We solve the second degree equation

u = [-5633.8 ±√(5633.8 2 + 4 48.03)] / 2

u = [- 5633.8 ± 5633.82] / 2

u₁ = 0.0085

u₂= -5633.81

u = tan θ

θ = tan⁻¹ u

For u₁

θ₁ = tan⁻¹ 0.0085

θ₁ = 0.487º

For u₂

θ₂ = -89.99º

The launch angle must be 0.487º

b) let's look for the time it takes for the arrow to arrive

x = v₀ₓ t

t = x / v₀ cos θ

t = 120 / (300 cos 0.487)

t = 0.400 s

The deer must be at a distance of

v = 20 mph (5280 ft / 1 mi) (1 h / 3600s) = 29.33 ft / s

x = v t

x = 29.33 0.4

x = 11.73 ft

3 0

3 years ago

Why isn't direct current used in transformers

Furkat [3]

Answer:

No, it will not and this has a historical importance. The reason is that transformers work via induction of electrical forces by changes in magnetic fields, so the constat fields produced by dc currents won't work at all

Explanation:

4 0

2 years ago

Read 2 more answers