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vitfil [10]
3 years ago
14

Question 1 Multiple Choice Worth 2 points)

Physics
1 answer:
Vinil7 [7]3 years ago
4 0

Answer:

2 atoms of oxygen in carbon dioxide

Explanation:

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heat

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A 70.0 kg skier is at rest at the top of a 120m hill. Assuming friction is negligible.
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49 m/s

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g A solid disk rotates in the horizontal plane at an angular velocity of rad/s with respect to an axis perpendicular to the disk
maksim [4K]

Complete question:

A solid disk rotates in the horizontal plane at an angular velocity of 0.067 rad/s with respect to an axis perpendicular to the disk at its center. The moment of inertia of the disk is 0.18 kg.m2. From above, sand is dropped straight down onto this rotating disk, so that a thin uniform ring of sand is formed at a distance of 0.40 m from the axis. The sand in the ring has a mass of 0.50 kg. After all the sand is in place, what is the angular velocity of the disk?

Answer:

The angular velocity of the disk is 0.0464 rad/s

Explanation:

Given;

initial angular velocity of disk, ωi = 0.067 rad/s

initial moment of inertia of the disk, I₁ =  0.18 kg.m²

radius of sand on the disk, R = 0.40 m

mass of sand, m = 0.50 kg

Initial angular momentum = Final angular momentum

I_i \omega_i = I_f \omega_f\\\\I_i \omega_i  = (I_{sand} + I_{disk})\omega _f

Moment of inertia of sand ring = MR²

\omega_f = \frac{I_i\omega_i}{I_{sand} +I_{disk}} = \frac{0.18*0.067}{MR^2 +0.18} \\\\\omega_f = \frac{0.18*0.067}{0.5*0.4^2 +0.18}= 0.0464 \ rad/s

Therefore, the angular velocity of the disk is 0.0464 rad/s

8 0
3 years ago
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