The complete question is as follows: The equilibrium constant, Kp, for the following reaction is 10.5 at 350 K: 2CH2Cl2(g) CH4(g) + CCl4(g) Calculate the equilibrium partial pressures of all species when CH2Cl2(g) is introduced into an evacuated flask at a pressure of 0.968 atm at 350 K. PCH2Cl2 = atm PCH4 = atm PCCl4 = atm
Answer: The equilibrium partial pressures of all species, that is,
,
and
is 0.420 atm, 0.420 atm and 0.128 atm.
Explanation:
For the given reaction equation, the initial and equilibrium concentration of involved species is as follows.
Initial: 0.968 atm 0 0
Equilibrium: (0.968 - 2x) x x
Now,
for this reaction is as follows.


Thus, we can conclude that the equilibrium partial pressures of all species, that is,
,
and
is 0.420 atm, 0.420 atm and 0.128 atm.
Answer: Time required to deposit an even layer of gold with given thickness is
sec.
Explanation:
The given data is as follows.
Surface area = 49.8
,
Density of gold = 19.3
,
Current = 3.15 A, thickness of gold layer = 
It is known that relation between volume, area and thickness is as follows.
V = Surface area × Thickness
= 
= 0.05988 
Therefore, we will calculate the time required to deposit an even layer of gold with given thickness is calculated as follows.

=
sec
Thus, we can conclude that time required to deposit an even layer of gold with given thickness is
sec.
Answer:
the awnser is 22
Explanation:
9+6 = 15 + 7 = 22 have a great day
Answer:
Every location on Earth experiences an average of 12 hours of light per day but the actual number of hours of daylight on any particular day of the year varies from place to place.
Considering the reaction:
3NO₂ + H₂O → 2HNO₃ + NO
To produce 3.56 moles of nitric acid, we require:
3.56 x 3/2 moles of NO₂
Moles of NO₂ = 5.34 moles of NO₂