Answer: endothermic
Explanation:
The cake (the subject) is receiving heat from the oven (its surroundings) in order to bake.
Answer:
The net charge on each lysine molecule would be -1.
Explanation:
- <u>When the pH is above 2.2</u> the deprotonated form of the carboxylic acid is more present, while the amino group and side chain (which is also amino) remain protonated (with a positive charge):
R-COOH ↔ R-COO⁻
R-NH₃⁺
R'-NH₃⁺
Net charge = +1
- <u>When pH is above 9.0</u>, the carboxyl group remains deprotonated, while the amino group is deprotonated and the side chain is protonated:
R-COOH ↔ R-COO⁻
R-NH₂
R'-NH₃⁺
Net charge = 0
- <u>When pH is above 10.5</u>, the carboxyl group remains deprotonated, while both the amino group and the side chain are deprotonated:
R-COOH ↔ R-COO⁻
R-NH₂
R'-NH₂
Net charge = -1
So at pH=13 (which is above 10.5) the net charge is -1.
Answer:
gibberish
Explanation:
its literaly nothing _#_$&_θГ[§θμθ_(;!&#\=&.·&:ГГ:¬¬&μ!¬´€
Volume = ?
Molarity (M) = 1.00 x 10⁻² M
moles (n) = 3.00 x 10⁻¹ mol
V = n / M
V = 3.00 x 10⁻¹ / 1.00 x 10⁻²
V = 30 L