Answer:
% Po lost = 100[1 - e^(-0.005t)] %; 73.0 g
Step-by-step explanation:
p(t) = 100e^(-0.005t)
Initial amount: p(0) = 100
Amount remaining: p(t) = 100e^(-0.005t)
Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]
% of Po lost = amount lost/initial amount × 100 %
= [1 - e^(-0.005t)] × 100 % = 100[1 - e^(-0.005t)] %
p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g
The mass of polonium remaining after 63 days is 73 g.
Answer:
[7, -4, -8]
Step-by-step explanation:
Just simply plug in each choice into the equations to confirm their authenticities.
Answer:
[-11/5,∞)
Step-by-step explanation:
1. Add 4 to both sides: 7x-4+4≥-15+2x+4
2. Simplify: 7x≥2x-11
3. Subtract 2x from both sides: 7x-2x≥2x-11-2x
4. Simplify: 5x≥-11
5. Divide both sides by 5: 5x/5≥-11/5
6. Simplify: -11/5
