Answer:
Explanation:
a )
Iz( t ) = A + B t²
Iz( t ) = angular velocity
putting dimensional formula
T⁻¹ = A + Bt²
A = T⁻¹
unit of A is rad s⁻¹
BT² = T⁻¹
B = T⁻³
unit of B is rad s⁻³
b )
Iz( t ) = A + B t²
dIz / dt = 2Bt
angular acceleration = 2Bt
at t = 0
angular acceleration = 0
at t = 5
angular acceleration = 2 x 1.6 x 5
= 16 rad / s²
Iz( t ) = A + B t²
dθ / dt = A + B t²
integrating ,
θ = At + B t³ / 3
when t = 0 , θ = 0
when t = 2
θ = At + B t³ / 3
= 2.65 x 2 + 1.6 x 2³ / 3
= 5.3 + 4.27
= 9.57 rad .
Flywheel turns by 9.57 rad during first 2 s .
THe loss of 2 protons and 2 neutrons (also called a helium nucleus) is defined as alpha decay.
Answer:
Answer part a:
Q= 10.62 MeV
Answer part b:
Energy of gamma particle is given by
E γ = 10.62 MeV
Explanation:
See attached file for explanation.
Explanation:
It is given that,
Mass of a bungee jumper is 65 kg
The time period of the oscillation is 38 s, hitting a low point eight more times.It means its time period is
After many oscillations, he finally comes to rest 25.0 m below the level of the bridge.
For an oscillating object, the time period is given by :
k = spring stiffness constant
So,
When the cord is in air,
mg=kx
x = the extension in the cord
So, the unstretched length of the bungee cord is equal to 25 m - 5.6 m = 19.4 m