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3 years ago

Please answer the questions before 12 am

Mathematics

2 answers:

Delvig [45]3 years ago

5 0

Answer:

Step-by-step explanation:

42)1.50/6=0.25

43)3/2=1.5

44)1x2=2

sdas [7]3 years ago

5 0

Answer:

42.) $0.25 per banana.

43.) 1.5 cakes per hour.

44.) 2 pounds of food per hour.

Step-by-step explanation:

42.)

$\frac{Cost}{Amount}=\frac{1.50}{6}=0.25$

43.)

$\frac{Amount}{Time}=\frac{3}{2}=1.5$

44.)

$\frac{Amount}{Time}=\frac{1}{0.5}=2$

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3 years ago

Read 2 more answers

An insurance institute conducted tests with crashes of new cars traveling at 6 mi/h. The total cost of the damages was found fo

Anettt [7]

Answer:

a. Mean = $6,358.2

b. median = $6,275

c. Mode = none

d. Midrange = $6,647.5

There is no much difference in the measures of center.

Step-by-step explanation:

==>Given:

$7,402, $4,819, $8,969, $6,275, $4,326

==>Required:

a. Mean: sum of all values in the given sample data ÷ number of values in the sample

Mean = ($7,402 + $4,819 + $8,969 + $6,275 + $4,326) ÷ 5

= $31,791 ÷ 5

Mean = $6,358.2

b. Median: this is the meddle value if the data set when ordered. Ordering the data set, we have:

$4,326, $4819, [$6,275], $7402, $8,969

Our median is $6,275.

c. Mode is the most common value in the data set. Therefore, we have no mode since there is no value in our data set that appears the most.

d. Mid-range = (highest value + lowest value) ÷ 2

= ($8,969 + $4,326) ÷ 2

= 13,295 ÷ 2 = $6,647.5

3 0

4 years ago

Find the indicated probability.

natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

Recall:

Binomial Distribution --> $P(k)={n\choose k}p^kq^{n-k}$
$P(k)$ denotes the probability of $k$ successes in $n$ independent trials
$p^k$ denotes the probability of success on each of $k$ trials
$q^{n-k}$ denotes the probability of failure on the remaining $n-k$ trials
${n\choose k}=\frac{n!}{(n-k)!k!}$ denotes all possible ways to choose $k$ things out of $n$ things

Given:

$n=10$
$k=4$
$p^k=0.53^4$
$q^{n-k}=(1-0.53)^{10-4}=0.47^6$
${n\choose k}={10\choose 4}=\frac{10!}{(10-4)!4!}=210$

Calculate:

$P(4)=(210)(0.53^4)(0.47^6)=0.1786117069\approx0.179$

Therefore, the probability that the archer will get exactly 4 bull's-eyes with 10 arrows in any order is 0.179

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2 years ago

A square pyramid has a base with an area of 20 square meters, and its lateral faces have a slant height of x meters. Sydney is c

DerKrebs [107]

1. Consider the pyramid ABCDE in the figure 1 attached:

Each side of the square base equals (units)

Area of 1 lateral side of pyramid ABCDE is

so the total lateral area is (units squared)

and the total surface area is (units squared)

2. Now consider the second figure KLMNP, Sydney's pyramid:

The lateral area is

so the total area of the second pyramid is

So 2 things can be said about the areas:

i) the lateral area of Sydney's pyramid is times larger than the lateral area of the original pyramid.

ii) The total area of Sydney's pyramid is units squared larger than the total area of the original pyramid.

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3 years ago

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AlladinOne [14]

He'll spend 138.91 dollars.

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3 years ago