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3 years ago

C is the midpoint of segment AE. The coordinates of C are (3, 8). The coordinates of E are (-5, 11). Find the coordinates of A.

Mathematics

1 answer:

kvv77 [185]3 years ago

7 0

Answer:

(-13,14)

Step-by-step explanation:

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Manny's parents came in to eat and he waited on them. Their bill was $45.20, and they left him a 35% tip. How much was his tip?

Sav [38]

Step-by-step explanation:

Use the equation ?/45.20 = 35\100 and what you get is your answer

Hope this helps

8 0

3 years ago

Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel

GarryVolchara [31]

Answer:

The unusual $X$ values for this model are: $X = 0, 1, 2, 7, 8$

Step-by-step explanation:

A binomial random variable $X$ represents the number of successes obtained in a repetition of $n$ Bernoulli-type trials with probability of success $p$ . In this particular case, $n = 8$ , and $p = 0.53$ , therefore, the model is ${8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}$ . So, you have:

$P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024$

$P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215$

$P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848$

$P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912$

$P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695$

$P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431$

$P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371$

$P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442$

$P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062$

The unusual $X$ values for this model are: $X = 0, 1, 7, 8$

6 0

3 years ago

Read 2 more answers

Please help im almost done

irga5000 [103]

Answer:

1/4

Step-by-step explanation:

the numerator is 12 because there are 12 possible outcomes. The numerator is 3 because there are 3 numbers in this set that are greater than 9. You get 3/12 which then simplifies to 1/4

8 0

3 years ago

Max correctly solved this inequality.

Dafna11 [192]

Answer:

Step-by-step explanation:

Got it right on edge. mark me brainliest please

6 0

3 years ago

Write Each Number As A Power Of 5

Lena [83]

The numbers as powers of 5 are 5^-1, 5^-2, 5^-3 and 5^0

<h3>How to rewrite the numbers as a power of 5?</h3>

The numbers are given as:

• 0.2

• 0.04

• 125^-1

• 15^0

<u>Number 1: 0.2</u>

Express as fraction

1/5

Apply the power rule of indices

5^-1

<u>Number 2: 0.04</u>

Express as fraction

1/25

Express 25 as 5^2

1/5^2

Apply the power rule of indices

5^-2

<u>Number 3: 125^-1</u>

Express as fraction

1/125

Express 125 as 5^3

1/5^3

Apply the power rule of indices

5^-3

<u>Number 4: 15^0</u>

Evaluate the exponent

15^0 = 1

Express 1 as 5^0

15^0 = 5^0

Hence, the numbers as a power of 5 are 5^-1, 5^-2, 5^-3 and 5^0