What is an equation of the line that passes through the point (3,-1)(3,−1) and is parallel to the line 5x+3y=65x+3y=6?
1 answer:
Step-by-step explanation:
5x+3y = 6
5x = 6 - 3y
5x = 3(2-y)
5x/3 = 2 - y
y = 2 - (5x/3)
slope = x coefficient.
= - 5/3
Perpendicular slopes must be opposite reciprocals of each other: m1 * m2 = –1
new slope = 3/5
the equation formula
y = mx + b
m = new slope = 3/5
y = (3x/5) + b
From the point given (3 , -1 )
x = 3.
y = -1
-1 = (9/5) + b
b =( -5/5) - (9/5)
b = - 14 / 5
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