What is the third most common gas found in the air we breath?

2 answers:

6 0

Explanation: The most common gas people breathe from clean air is nitrogen. Air is a mixture of gases, and the air on Earth contains about 78 percent nitrogen and about 21 percent oxygen. Argon, carbon dioxide neon, helium, methane, krypton, hydrogen and xenon are in much smaller amounts.

Setler [38]2 years ago

6 0

Answer: Carbon dioxide

Explanation:

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When water evaporates, what happens to the molecules that make up the liquid water?

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Answer:

Evaporation happens when a liquid substance becomes a gas. When water is heated, it evaporates. The molecules move and vibrate so quickly that they escape into the atmosphere as molecules of water vapor.

Explanation:

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how many grams of calcium chloride can be prepared from 60.4 G of calcium oxide and 69.0 G of hydrochloric acid and a double dis

Ksenya-84 [330]

Balanced equation:
CaO + 2 HCl --> CaCl2 + H2O 
Calculate moles of each reactant: 
60.4 g CaO / 56.08 g/mol = 1.08 mol CaO 
69.0 g HCl / 36.46 g/mol = 1.89 mol HCl 

Identify the limiting reactant: 
Moles CaO needed to react with all HCl: 
1.89 mol HCl X (1 mol CaO / 2 mol HCl) = 0.946 mol CaO 
Because you have more CaO than that available, HCl is the limiting reactant. 

Calculate moles and mass CaCl2: 
1.89 mol HCl X (1 mol CaCl2 / 2mol HCl) X 111.0 g/mol = 105 g CaCl2

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Which substance is most likely a lipid? -long chains of molecules composed of carbon, hydrogen, and oxygen atoms -compounds that

gulaghasi [49]

Answer:

The answer is

Explanation:

- A nonpolar organic compound that is insoluble in water

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3 years ago

Why are most household items made up of oxygen?

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It is in our atmosphere

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3 years ago

A compound in a copper ore has the following percentage composition by mass:

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1) since we are given percentages, we can assume we have 100 grams of the molecule.

55.6 % Cu ----> 55.6 grams Cu
16.4 % Fe------> 16.4 grams Fe
28.0% S--------> 28.0 grams S

2) convert each gram to moles using the molar masses given

$55.6 g Cu \frac{1 mol}{63.5 g} = 0.876 mol Cu$
$16.4 g Fe \frac{1 mol}{56.0 g} = 0.293 mol Fe$
$28.0 gS \frac{1 mol}{32.0} = 0.875 mol S$

3) we divide the smallest value of moles (0.293) to each one.

Cu --> 0.876 / 0.293= 3
Fe---> 0.293 / 0.293= 1
S-----> 0.875 / 0.293= 3

4) let's write the empirical formula

Cu₃FeS₃

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2 years ago