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Sphinxa [80]
3 years ago
14

When the glucose solution described in part A is connected to an unknown solution via a semipermeable membrane, the unknown solu

tion level rises. Based on this information, what can be said about these two solutions
Chemistry
1 answer:
gtnhenbr [62]3 years ago
3 0

Answer:

The unknown solution had the higher concentration.

Explanation:

When two solutions are separated by a semi-permeable membrane, depending on the concentration gradient between the two solutions, there is a tendency for water molecules to move across the semi-permeable in order to establish an equilibrium concentration between the two solutions. This movement of water molecules across a semi-permeable membrane in response to a concentration gradient is known as osmosis. In osmosis, water molecules moves from a region of lower solute concentration or higher water molecules concentration to a region of higher solute concentration or lower water molecules concentration until equilibrium concentration is attained.

Based on the observation that when the glucose solution described in part A is connected to an unknown solution via a semipermeable membrane, the unknown solution level rises, it means that water molecules have passed from the glucose solution through the semipermeable membrane into the unknown solution. Therefore, the solution has a higher solute concentration than the glucose solution.

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Answer:

O Generation of electricity

Explanation:

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7 0
2 years ago
If a radioactive isotope has a half-life of 26.5 days, how many days does it take for a sample of the isotope to decrease by 35.
dangina [55]

Answer:

16.5 days

Explanation:

Given that:

Half life = 26.5 days

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{26.5}\ days^{-1}

The rate constant, k = 0.02616 days⁻¹

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given:

35.0 % is decomposed which means that 0.35 of [A_0] is decomposed. So,

\frac {[A_t]}{[A_0]} = 1 - 0.35 = 0.65

t = 7.8 min

\frac {[A_t]}{[A_0]}=e^{-k\times t}

0.65=e^{-0.02616\times t}

<u>t = 16.5 days.</u>

7 0
3 years ago
Which solution is the most concentrated? 2.0 mL of 10 M H2SO4, where H2SO4 has a molar mass of 98 g/mol 5.0 mL of 1.0 M PbSO4, w
marishachu [46]

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Explanation:

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Molartity is the concentration of the solution expressed as number of moles of solute per liters of solution.

The formula of molarity, M, is:

M = number of moles of solute / volume of solution in liters

2) 2.0 mL of 10 M H₂SO₄, where H₂SO₄ has a molar mass of 98 g/mol

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3) 5.0 mL of 1.0 M PbSO₄, where PbSO₄ has a molar mass of 303 g/mol

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4) 2.0 mL of 10.5 M H₂O₂, where H₂O₂ has a molar mass of 34 g/mol

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5) 100 mL of 10 M NaCl, where NaCl has a molar mass of 58 g/mol

⇒ concentration is 10 M

7 0
4 years ago
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What percentage of strontium-90 remains in a sample after three half-lives have passed? 12.5% 15% 25% 60%?
Lyrx [107]

12.5% of strontium-90 would remain in a sample after three half-lives have passed. Half-life automatically means 50% of the original amount would remain.

4 0
3 years ago
Read 2 more answers
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Answer:

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