Answer:
The answer to your question is: yield = 56.27%
Explanation:
Data
CH3CH2CH2CH2OH (l) → CH3 CH2CH2CH2Br
18.54 ml 1-butanol 15.65 g of 1-bromobutane
% yield = ?
density = 0.81 g/ml
MM = 74 g 1- butanol
MM = 137 g 1-bromobutane
Process
Calculate mass of 1- butanol
density = mass/volume
mass = density x volume
mass = 0.81 x 18.54
mass = 15.02 g of 1-butanol
Theoretical yield
74 g of 1- butanol ----------------- 137 g of 1-bromobutane
15.02 g of 1- butanol ------------- x
x = (15.02 x 137) / 74
x = 27.81 g of 1-bromobutane
% yield = experimental yield / theoretical yield x 100
% yield = 15.65 / 27.81 x 100
% yield = 56.28
Answer:
Here's what I get
Explanation:
At the introductory level of chemistry, I can think of only two situations when you use Greek prefixes.
They indicate the number of atoms or groups in a molecule when you are naming a compound.
1. Binary covalent compounds
For example, P₂S₅ is diphosphorus pentasulfide.
2. Hydrates
For example, Na₂SO₄·10H₂O is sodium sulfate decahydrate.
Answer:
cold
Explanation:
cold is when it get high on lattitude
In any balanced
chemical reaction, the elements or compounds which are located in the left hand
side of the arrow is the reactants while those that are location on the right
hand side are the products, therefore the product here is:
<span>CaO or Calcium Oxide</span>
