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statuscvo [17]
3 years ago
13

Can you describe the situations when Greek prefixes are used?

Chemistry
1 answer:
Black_prince [1.1K]3 years ago
7 0

Answer:

Here's what I get  

Explanation:

At the introductory level of chemistry, I can think of only two situations when you use Greek prefixes.

They indicate the number of atoms or groups in a molecule when you are naming a compound.

1. Binary covalent compounds

For example, P₂S₅ is diphosphorus pentasulfide.

2. Hydrates

For example, Na₂SO₄·10H₂O is sodium sulfate decahydrate.

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mrs_skeptik [129]
Well Mendeleev<span> predicted the existence and properties of elements that werent discovered at the time</span>
3 0
3 years ago
Three Stoichiometry Questions
andrezito [222]

Answer:

Explanation:

7)

Given data:

Mass of aluminium = 2.5 g

Mass of oxygen = 2.5 g

Mass of aluminium oxide = 3.5 g

Percent yield = ?

Solution:

Chemical equation:

4Al + 3O₂   →   2Al₂O₃

Number of moles of Al:

Number of moles = mass/ molar mass

Number of moles = 2.5 g/ 27 g/mol

Number of moles = 0.09 mol

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 2.5 g/ 32 g/mol

Number of moles = 0.08 mol

Now we will compare the moles of aluminium oxide with aluminium and oxygen.

                          Al         ;       Al₂O₃

                           4         :        2

                        0.09      :       2/4×0.09 = 0.045

                          O₂       :        Al₂O₃

                          3         :          2

                         0.08    :        2/3 ×0.08 = 0.053

The number of moles of aluminium oxide produced by Al are less so it will limiting reactant.

Mass of aluminium oxide:

Mass = number of moles × molar mass

Mass = 0.045  × 101.96 g/mol

Mass = 4.6 g

Percent yield:

Percent yield = actual yield / theoretical yield ×100

Percent yield = 3.5 g / 4.6 ×100

Percent yield = 76.1%

8)

Given data:

Mass of copper produced = 3.47 g

Mass of aluminium = 1.87 g

Percent yield = ?

Solution:

Chemical equation:

2Al + 3CuSO₄   →   Al₂(SO₄)₃ + 3Cu

Number of moles of Al:

Number of moles = mass/ molar mass

Number of moles = 1.87 g/ 27 g/mol

Number of moles = 0.07 mol

Now we will compare the moles of copper with aluminium.

                          Al         ;       Cu

                           2         :        3

                        0.07      :       3/2×0.09 = 0.105

             

Mass of copper:

Mass = number of moles × molar mass

Mass = 0.105  × 63.55 g/mol

Mass = 6.67 g

Percent yield:

Percent yield = actual yield / theoretical yield ×100

Percent yield =  3.47 g / 6.67 × 100

Percent yield = 52%

                       

4 0
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Identify the location of reduction in an electrochemical cell. group of answer choices the electrode the anode the socket the ca
stepladder [879]

The location of reduction in an electrochemical cell is called the anode.

An electrochemical cell ( galvanic cell ) is generate electric energy from chemical reactions. In galvanic cell species ( for example zinc and zinc cations ) from one half-cell lose electrons ( oxidation ) and species from other half-cell ( for example copper and copper cations ) gain electrons ( reduction ).  Electric current is generated due to the flow of electrons from the anode that undergoes an oxidation reaction to the cathode which has a reduction reaction in the circuit of an outer wire circuit.

to learn more about  electrochemical cell

brainly.com/question/22433727

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igor_vitrenko [27]

Answer:

first ionization energy is the amount of energy required to remove an electron from isolated gaseous atom

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it's my opinion am not sure ok

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